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Darina [25.2K]
3 years ago
7

I Need HELP!how do you figure out 22/7=5/X

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0
\frac{22 }{7}= \frac{5}{x} \\ \\ x\neq 0 \\ \\ 22x=7*5\\ \\22x=35 \ \ /:22 \\ \\x=\frac{35}{22}\\ \\x=1\frac{23}{25}
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Pa help po sana plsss
Anna71 [15]

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2 years ago
NEED HELP FAST PLEASE!! Draw the base plan for the set of stacked cubes, assume the no cubes are hidden from view.
Mazyrski [523]
Assuming no cubes are hidden from view, the base view (as if you're looking from underneath the figure) would have a 2 x 2 square of cubes, plus one at the top.  This means that your correct choice would be the one I've attached.

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3 years ago
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What is the probability that a fair die never comes up an even number when it is rolled six times? (note: enter the value of pro
seropon [69]
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:

Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.

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6 0
3 years ago
|x - 7| - |x - 2| = 3
rewona [7]
|x-7| - |x-2| = 3

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7 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
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