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Darina [25.2K]
3 years ago
7

I Need HELP!how do you figure out 22/7=5/X

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0
\frac{22 }{7}= \frac{5}{x} \\ \\ x\neq 0 \\ \\ 22x=7*5\\ \\22x=35 \ \ /:22 \\ \\x=\frac{35}{22}\\ \\x=1\frac{23}{25}
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They have a band around them close to the ‘front end, ' sorry if this doesn't help, lol. :)

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A student solved this problem and said the answer was hour. cindy rode her bike for hour and ran for hour. what was the total le
saw5 [17]

The answer would be a. Yes, the student’s answer is reasonable.

In the problem, it states that Cindy rode her bike for an hour and ran for an hour.  Without the presence of the comma between rode her bike for an hour, and ran for an hour, this just means that Cindy only rode her bike and ran it for an hour.

The sentence can be written as Cindy rode her bike and ran for an hour.  So, this gives an answer that Cindy only exercise for an hour.

6 0
3 years ago
In the last baseball game, there were two 3-run home runs and 4 hits that each scored 2 runs. Write in algebraic expression to m
Aloiza [94]
Let the number of runs made on the home run be x, then for the <span>two 3-run home runs, we have 2x

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Thus the algebraic expression to model the total score is 2x + 4y.

Because, there are 3 runs per home run, then x = 3 and because there are 2 runs per hit, then y = 2.

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</span>
7 0
3 years ago
Donal currently has 7,200 points in his fantasy baseball league, which is 20% more points than Scott How many points does Scott
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Answer:

5760

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7 0
3 years ago
Three consecutive odd integers have a sum of 27. Find the integers.
jek_recluse [69]

\sf \bf {\boxed {\mathbb {GIVEN:}}}

Sum of three consecutive odd integers = 27

\sf \bf {\boxed {\mathbb {TO\:FIND:}}}

The values of the three integers.

\sf \bf {\boxed {\mathbb {SOLUTION:}}}

\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

Let us assume the three consecutive odd integers to be x, (x+2) and (x+4).

As per the condition, we have

Sum \:  \:  of \:  \:  the  \:  \: three \:  \:  consecutive \:  \:  odd \:  \:  integers  = 27

➺ \: x + (x + 2) + (x + 4) = 27

➺ \: x + x + 2 + x + 4 = 27

Now, collect the like terms.

➺ \: (x + x + x) + (2 + 4) = 27

➺ \: 3x + 6 = 27

➺ \: 3x = 27 - 6

➺ \: 3x = 21

➺ \: x =  \frac{21}{3} \\

➺ \: x = 7

Therefore, the three consecutive odd integers whose sum is 27 are \boxed{  7  }, \boxed{ 9   } and \boxed{ 11   } respectively.

\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}

⇢ 7 + 9 + 11 = 27

⇢ 27 = 27

⇢ L. H. S. = R. H. S.

\sf\blue{Hence\:verified.}

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

4 0
3 years ago
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