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Luda [366]
3 years ago
15

Which expression is equivalent to i²³³? 1 –1 i –i

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0
I^233 = (i^4)^((58) + 1) = (i^4)^58 * i^1 = 1 * i = i
Paraphin [41]3 years ago
6 0
I hope this helps you

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1) Kyla paid a rental company a one-time fee of $100 plus $25 per day to rent a car. For
IrinaVladis [17]

Answer:

14 days

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

25n+100=450

Step 2: Subtract 100 from both sides.

25n+100−100=450−100

25n=350

Step 3: Divide both sides by 25.

25n/25 =350/25

n=14

5 0
3 years ago
Read 2 more answers
Bill rented a truck for one day. There was a base fee of $16.99, and there was an additional charge of 92 cents for each mile dr
Lady_Fox [76]

Answer:

He paid $18 of which $15.95 was

the flat fee.

 18.00

- 15.95

---------

$2.05 is the amount paid for mileage.

 

This is 205 cents for mileage

at 71 cents per mile.  Divide

205 by 71 to get the miles driven.

 

205/71 = 2.9 miles.

Step-by-step explanation:

7 0
3 years ago
The sum of two numbers is 67. the smaller number is 3 less than the larger number. what are the two numbers?
V125BC [204]
Let the larger number be x
The smaller number would be x-3 

(x-3)+x=67 
2x-3=67 
2x=67-3 
2x=64 
x=64/2 
x=32 

Therefore the larger number is 32 and the smaller is (32)-3= 29 

Hope I helped :) 
7 0
3 years ago
!!20 POINTS!!<br> What are the names of three collinear points?
maks197457 [2]

Answer: L, J, K

Step-by-step explanation:

L, J, and K are collinear because they all lie on the same line.

8 0
3 years ago
DATA ANALYSIS AND STATISTICSProbabilities involving two rolls of a dieAn ordinary (falr) die is a cube with the numbers 1 throug
Zepler [3.9K]

Solution

The table below is the required sample space of the to fair die

From the above table

The sample space contain 36 outcomes

Event A: The sum is greater than 9

we will look at the table and count all the elements that are greater than 9

There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)

The probability for event A will be

\begin{gathered} p(A)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(A)=\frac{6}{36} \\ p(A)=\frac{1}{6} \end{gathered}

P(A) = 1/6

Event B: The sum is an even number.

We will look at the table and count the number of elements that are even

There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)

The probability for event B will be

\begin{gathered} p(B)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(B)=\frac{18}{36} \\ p(B)=\frac{1}{2} \end{gathered}

p(B) = 1/2

5 0
1 year ago
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