Question

Graph a line that has a slope of -3 and contains the point (4,-2)

Answer 1

Answer:

The equation of the line is:

$y = -3x+10$

The graph is attached below.

Step-by-step explanation:

Given that the line has a slope of -3, so

m = -3

As the point contains the point (4, -2), so we can use the point-slope form of the line equation to determine the line.

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

so substituting the values m = -3 and the point (4, -2)

$y-y_1=m\left(x-x_1\right)$

$y - (-2) = -3(x-4)$

$y+2 = -3x+12$

$y = -3x+12-2$

$y = -3x+10$

Therefore, the equation of the line is:

$y = -3x+10$

The graph is attached below.