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torisob [31]
3 years ago
12

Graph a line that has a slope of -3 and contains the point (4,-2)

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0

Answer:

The equation of the line is:

y = -3x+10

The graph is attached below.

Step-by-step explanation:

Given that the line has a slope of -3, so

m = -3

As the point contains the point (4, -2), so we can use the point-slope form of the line equation to determine the line.

Point slope form:

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

so substituting the values m = -3 and the point (4, -2)

y-y_1=m\left(x-x_1\right)

y - (-2) = -3(x-4)

y+2 = -3x+12

y = -3x+12-2

y = -3x+10

Therefore, the equation of the line is:

y = -3x+10

The graph is attached below.

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Answer:

First Step: separate x^2 from -16

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x^2 - 16/25 = 0

^^ this might be easier if you separate x^2 and -16

<em>First Step-</em>

so rewrite the problem as x^2/25  -16/25 = 0

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<em>Second Step-</em>

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<em>Continuation-</em>

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