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Igoryamba
3 years ago
11

99 POINTS!A certain triangle has an area of 120 m². The base is 7 m longer than the height. Please find the height. Show a coupl

e steps.
Mathematics
1 answer:
nydimaria [60]3 years ago
7 0
What type of triangle is it? Does it matter?
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Evaluate the integral Integral from (5 comma 2 comma 4 )to (7 comma 9 comma negative 3 )y dx plus x dy plus 3 dz by finding para
padilas [110]

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_{(5,2,4)}^{(7,9,-3)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz

Parameterize the line segment (call it C) by

\vec r(t)=(1-t)(5\,\vec\imath+2\,\vec\jmath+4\,\vec k)+t(7\,\vec\imath+9\,\vec\jmath-3\,\vec k)

\vec r(t)=(2t+5)\,\vec\imath+(7t+2)\,\vec\jmath+(4-7t)\,\vec k

with 0\le t\le1. Then

\vec r'(t)=2\,\vec\imath+7\,\vec\jmath-7\,\vec k

and the line integral is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1((7t+2)\,\vec\imath+(2t+5)\,\vec\jmath+3\,\vec k)\cdot\vec r'(t)\,\mathrm dt

=\displaystyle\int_0^1((2t+5)+2(7t+2)-21)\,\mathrm dt

=\displaystyle\int_0^1(28t+18)\,\mathrm dt=\boxed{32}

Alternatively, if we can show that \vec F is conservative, then we can apply the fundamental theorem of calculus. We need to find f such that \nabla f=\vec F, which requires

\dfrac{\partial f}{\partial x}=y

\dfrac{\partial f}{\partial y}=x

\dfrac{\partial f}{\partial z}=3

Integrating both sides of the first equation with respect to x gives

f(x,y,z)=xy+g(y,z)

Differentiating both sides wrt y gives

\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}

\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

Differentiating wrt z gives

\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}

\implies h(z)=3z+C

So we have

f(x,y,z)=xy+3z+C

and \vec F is conservative. By the FTC, we find

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=f(7,9,-3)-f(5,2,4)=\boxed{32}

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