Answer:
Step-by-step explanation:
Let the length and breadth of the rectangle be a,b units respectively.
Then the area will be ab square units.
Now if the length of the rectangle is reduced by 5 units and breadth is increased by 2 units then new length and breadth will be (a−5) units and (b+2) units.
Then new area will be (a−5)(b+2).
Then according to the problem,
(a−5)(b+2)−ab=−80
or, 2a−5b=−70.......(1).
Now if length of the rectangle is increased by 10 units and breadth is decreased by 5 units then new length and breadth will be (a+10) units and (b−5) units.
Then new area will be (a+10)(b−5).
Then according to the problem,
(a+10)(b−5)−ab=50
or, 10b−5a=100
or, 2b−a=20
or, 4b−2a=40......(2).
Now adding (1) and (2) we get
−b=−30
or, b=30.
Putting the value of b in (1) we get, a=40.
Now a+b=40+30=70.
Answer:
10
Step-by-step explanation:
In order to solve this question we first have to break down the terms.
Sum = Adding
Times = Multiplying.
The question states "3 times the sum of a number n and 12 is 45". In written form, it would be the following:
3(12+n) = 45
To solve this you first divide both sides by three and you'd be left with the following:
(12+n) = 15.
Then subtract 12 from both sides. Leaving you with:
n = 3
Value of 3/4 + 1/5 is 19/20.
Do you need the steps?
First, calculate the LCM of the denominators (4 and 5) which is 20.
Now, divide 20 by 4 and 5 and multiply the quotient with the numerator.
=>
<u> </u><u>(</u><u>5</u><u>×</u><u>3</u><u>)</u><u> </u><u>+</u><u> </u><u>(</u><u>4</u><u>×</u><u>1</u><u>)</u><u> </u><u> </u>
20
=> <u>15+4</u>
20
=> 19/20
Hope it helps!
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