Supposing 30 days in the month of May (which is not always same in every year),we have,
S= Sample Space
n(S)=total days in a year=365 days
n(E)=no of favourable events
= no of days in the month of May=30 days
Then the probability is of favourable events is,
P(E)=n(E)/n(S)=30/365=6/73
Now,the probability that the birthday is not in May is,
P'(E) =1-6/73=67/73 ANS!!!
M.N and O are 60 degree. And you have to know that 30 60 and 90 triangle. if 30 degrees opposite is measuring A , 60 is A square root 3 and the 90's opposite is being 2A. So 90 degree opposite is 16 square root 3 and 30 degree is being 8 square root 3 and 60 is

the height is 24 .
Answer:
<em>26 ft^2</em>
Step-by-step explanation:
Let us imagine a rectangle around this figure, provided a rectangle with dimensions 5 feet by 7 feet. If we were to subtract the non - shaded region in this rectangle from the rectangle's area itself, it would save as some time to solve for the area of the shaded region;
<em>Area of Outer Rectangle ⇒ 5 * 7 = 35 ft^2</em>,
Now this non - shaded region is composed of a triangle and a rectangle, the triangle having dimensions 3 by 2 feet, the rectangle being 2 by 3 feet consecutively;
<em>Area of triangle ⇒ 1/2 * base * height = 1/2 * 3 * 2 = 3 ft^2</em>,
<em>Area of rectangle ⇒ length * width = 2 * 3 = 6 ft^2</em>
Thus the area of the shaded region is: 35 - 3 - 6 = 26 ft^2;
<em>Answer: 26 ft^2</em>
Answer:
5
Step-by-step explanation:
what kind of question is this
Answer:
SAS Similarity Theorem
Step-by-step explanation:
we know that
<u>SAS Similarity Theorem</u>: States that if two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar
In this problem
∠HJZ=∠RJW ----> by vertical angles
and
WJ/HJ=JR/JZ
substitute the values
8/4=6/3
2=2 ----> is true
so
Two sides of triangle HJZ are proportional with the two corresponding sides of triangle WJR and the included angle is congruent
therefore
Triangles are similar by SAS Similarity Theorem