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3 years ago

The end points of a diameter of a circle are (6,2) and (-4,7).

Mathematics

1 answer:

nata0808 [166]3 years ago

8 0

Answer:

Step-by-step explanation:

The standard form equation of a circle with radius r is expressed as

( x − h )^2 + ( y − k )^2 =r ^2 ,

where r represents the radius

h and k are the coordinates of the center of the circle C( h , k )

To determine the coordinates at the center of the circle, the midpoint formula would be used. It is expressed as

[(x1 + x2)/2 , (y1 + y2)/2]

Midpoint of the circle =

(6 - 4)/2 , (2 + 7)/2 = (1, 4.5)

h coordinate of the center = 1

k coordinate of the center = 4.5

r^2 = (x - h)^2 + (2 - k)^2

r^2 = (6 - 1)^2 + (2 - 4.5)^2

r^2 = 5^2 + (- 2.5)^2 = 25 + 6.25

r^2 = 31.25

Substituting r^2 = 31.25, h = 1 and k = 4.5 into (x − h )^2 + ( y − k )^2 = r^2, the standard equation of the circle becomes

(x − 1 )^2 + ( y − 4.5 )^2 = 31.25

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Natalija [7]

Sorry it is a bit messy but the answer is right

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3 years ago

Read 2 more answers

2.) I am a two-digit number that can be referred to as a perfect square. The sum of my two digits is 10. What number am I?

Scorpion4ik [409]

Answer: 64

Step-by-step explanation:

By definition, a perfect square is the square of a whole number.

The information given in the problem that you must keep on mind is:

- The number has two digits.

- The number is a perfect square ( Is obtained by squaring a whole number).

- The sum of its two digits is 10.

The number 64 is formed by the digit 6 and the digit 4. The sum of both digits is:

$6+4=10$

The number 64 can be written as:

$64=8*8=8^2$

Then, it is perfect square.

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3 years ago

During a Grand Prix car race, the tyres on a car are reduced in mass by 3%. If their mass is 388 kg at the end of the race, what

spayn [35]

Answer:

Their mass at the start was 400 kg.

Step-by-step explanation:

Given:

The tyres on a car during a grand prix race are reduced in mass by 3%. Their mass is 388 kg at the end of the race.

Now, to find the mass at the start.

Let the mass at the start be $x$ .

According to question:

$x - 3 \%ofx= 388$

⇒ $x-\frac{3}{100}\times x = 388$

⇒ $x-0.03x =388$

⇒ $0.97x=388$

Dividing both sides by 0.97 we get:

⇒ $x=400$

Therefore, their mass at the start was 400 kg.

8 0

4 years ago

The distance between two points, a and b, on a number line is expressed as

rusak2 [61]

The distance between points (a) and (b) is the number of units between the points.

Formula for halfway two

Assume the lesser point is point (a)

To locate the halfway between points (a) and (b)

Calculate the absolute difference between points (a) and (b) i.e. |a - b|
Divide the difference into halves
Add the value of one half to point (a).

The above steps is represented as:

$P = a + \frac{|a - b|}{2}$

Using the above formula, the halfway point between 5 and 11 would be 8

The formula can be used to calculate the distance between negative points, and absolute values are used to determine the number of units between the points

Real world circumstance

The formula can be used to calculate the halfway distance between two points on a track

Fractional distance

To determine the fractional distance, we simply replace the 1/2 in the original formula with the appropriate fraction.

Take for instance, three-fourths from (a) to (b) would be:

$P = a + \frac{3|a - b|}{4}$