Answer:
H=12
Step-by-step explanation:
Khan said so
Answer:
6y-6y, cancel it out to find x first.
-5x+6y=41
7x-6y=-43
2x=-2
Step-by-step explanation:
i hope this helps :)
Given:

To find:
The value of f'(x).
Solution:
Formulae used:



Chain rule:
![\dfrac{d}{dx}[f(g(x))]=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%3Df%27%28g%28x%29%29g%27%28x%29)
Where C is an arbitrary constant.
We have,

Differentiate with respect to x.


Therefore, the required values is
.
Would assume this to be: n² + 50
First term, n=1, n² + 50 = 1² + 50 = 1*1 + 50 = 1 + 50 = 51
Second term, n=2, n² + 50 = 2² + 50 = 2*2 + 50 = 4 + 50 = 54
Third term, n=3, n² + 50 = 3² + 50 = 3*3 + 50 = 9 + 50 = 59
First three terms are: 51, 54, & 59.