The first four terms of sequence is 20, -10, -40, -70
<em><u>Solution:</u></em>
Given that we have to find the first four terms of sequence
<em><u>Given recursive formula is:</u></em>
![a_n = 20 - 30(n-1)](https://tex.z-dn.net/?f=a_n%20%3D%2020%20-%2030%28n-1%29)
<em><u>To find the first term, substitute n = 1</u></em>
![a_1 = 20-30(1-1)\\\\a_1 = 20-30(0)\\\\a_1 = 20](https://tex.z-dn.net/?f=a_1%20%3D%2020-30%281-1%29%5C%5C%5C%5Ca_1%20%3D%2020-30%280%29%5C%5C%5C%5Ca_1%20%3D%2020)
Thus the first term of sequence is 20
<em><u>To find the second term, substitute n = 2</u></em>
![a_2 = 20-30(2-1)\\\\a_2 = 20-30(1)\\\\a_2 = 20-30\\\\a_2 = -10](https://tex.z-dn.net/?f=a_2%20%3D%2020-30%282-1%29%5C%5C%5C%5Ca_2%20%3D%2020-30%281%29%5C%5C%5C%5Ca_2%20%3D%2020-30%5C%5C%5C%5Ca_2%20%3D%20-10)
Thus the second term of sequence is -10
<em><u>To find the third term, substitute n = 3</u></em>
![a_3 = 20-30(3-1)\\\\a_3 = 20-30(2)\\\\a_3 = 20-60\\\\a_3 = -40](https://tex.z-dn.net/?f=a_3%20%3D%2020-30%283-1%29%5C%5C%5C%5Ca_3%20%3D%2020-30%282%29%5C%5C%5C%5Ca_3%20%3D%2020-60%5C%5C%5C%5Ca_3%20%3D%20-40)
Thus the third term of sequence is -40
<em><u>To find the fourth term, substitute n = 4</u></em>
![a_4 = 20-30(4-1)\\\\a_4 = 20-30(3)\\\\a_4 = 20-90\\\\a_4 = -70](https://tex.z-dn.net/?f=a_4%20%3D%2020-30%284-1%29%5C%5C%5C%5Ca_4%20%3D%2020-30%283%29%5C%5C%5C%5Ca_4%20%3D%2020-90%5C%5C%5C%5Ca_4%20%3D%20-70)
Thus the first four terms of sequence is 20, -10, -40, -70