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7nadin3 [17]
3 years ago
9

kayleigh is pucharsing organic carrots for her pet rabbit.The store has a 5 pound bag for $9.45 for an 8 for $13.68 Which bag wo

uld be the better buy overall​
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer: The 8 pound bag

Step-by-step explanation: you divide 9.45 by 5 and you get the unit rate of 1.89 and then you divide 13.68 by 8 and you get the unit rate of 1.71 which means the 8 pound bag is cheaper.

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- 4x + 8y = 20<br> ----4x + 2y = -30
snow_tiger [21]

Answer:

40

Step-by-step explanation:

5 0
3 years ago
PLS HELP IM BEGGING U
expeople1 [14]

Answer:

answer is 57.

Step-by-step explanation:

Given

m<6= x - 8

m<7 = 2x - 7

We know

<6 + <7 = 180° [ being linear pair ]

x - 8 + 2x - 7 = 180°

3x - 15 = 180°

3x = 180° + 15°

3x = 195°

x = 195° / 3

x = 65°

Now

m<6= x - 8 = 65° - 8° = 57°

hope it helps :)

8 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
3/8 as a decimal I need help
vovangra [49]

Answer:

0.375

Step-by-step explanation:

= 3/8

= 3 ÷ 8

= 0.375

7 0
3 years ago
Read 2 more answers
Find the area of the parallelogram that has a base of 4m and a height of 5.5m.
Sveta_85 [38]

Answer:

22m²

Step-by-step explanation:

Area of parallelogram is simply the base length x height.

In this case, base length = 4m and height = 5.5m

hence,

Area = 4 x 5.5 = 22m²

3 0
3 years ago
Read 2 more answers
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