The main property is as follow
(A^p)^q=A^pxq
so only Sam's work is correct because
(8^4)^5 x(7^3)^9=(8^4x5)x(7^3x9)=8^20x 7^27
Subtract 4 from both sides, solve using quadratic formula
ax^2+bx+c
(-b(+or-) Square Root of b^2 - 4ac)/2a
9x^2+9x-4=0
-9(+or-)Square root of 9^2-4(9)(-4)/2(9)
Solve^
The answer to this question mark will do it all in a few weeks to make it happen again this week at the end
Answer:
The first one: {{7, 12), (1, -5), (3, -10), (2, -5)}
Step-by-step explanation:
Functions can't have repeating x values. Each x has to have its own y value.
For when x=2, You get 14.
For when x=3, You get 11.
Therefore, x=2 gives a bigger value.
