Answer:
25 kg.
Step-by-step explanation:
the dog is approximately 55 pounds and we know 1 kg is approximately 2.2 pounds. 55 divided by 2.2 is 25. the dog is approximately 25 kg.
Answer:
Here's what I get
Step-by-step explanation:
aₙ is the nth term in the arithmetic sequence and aₙ₋₁ is the term that comes immediately before it in the sequence.
We know that a₅ = 23. To find a₈, we must find a₆ and a₇.
a₅ = 23
a₆ = a₅ + 5 = 23 + 5 = 28
a₇ = a₆ + 5 = 28 + 5 = 33
a₈ = a₇ + 5 = 33 + 5 = 38
Answer:X=110/121
Step-by-step explanation:
Multiply 100 by 1.21 then by x
121x=110
Divide both side by 121
X=110/121
X=0.91
Answer:
The watered area is approximately 3783 square feet.
Step-by-step explanation:
The area that is watered due to the rotation of the spankler is a circular section area (
), whose formula is:
![A = \frac{\theta }{2}\times \frac{1}{360^{\circ}}\times 2\pi \times d^{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B%5Ctheta%20%7D%7B2%7D%5Ctimes%20%5Cfrac%7B1%7D%7B360%5E%7B%5Ccirc%7D%7D%5Ctimes%202%5Cpi%20%5Ctimes%20d%5E%7B2%7D)
Where:
- Water distance, measured in feet.
- Rotation angle, measured in sexagesimal degrees.
Given that
and
, the watered area is:
![A = \frac{60^{\circ}}{2} \times \frac{1}{360^{\circ}}\times 2\pi \times (85\,ft)^{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B60%5E%7B%5Ccirc%7D%7D%7B2%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7B360%5E%7B%5Ccirc%7D%7D%5Ctimes%202%5Cpi%20%5Ctimes%20%2885%5C%2Cft%29%5E%7B2%7D)
![A \approx 3783\,ft^{2}](https://tex.z-dn.net/?f=A%20%5Capprox%203783%5C%2Cft%5E%7B2%7D)
The watered area is approximately 3783 square feet.
Answer by JKismyhusbandbae:
x - 10 ≤ 19
x - 10 + 10 ≤ 19 + 10
x ≤ 29
x - 10 ≥ - 19
x - 10 + 10 ≥ - 19 + 10
x ≥ - 9
Answer: - 9 ≤ x ≤ 29