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sasho [114]
4 years ago
13

On January 1, 1990, Emilio deposited $1650 into a savings account paying 6.2% interest compounded monthly. If he hasn't made any

additional deposits or withdrawals since then, and if the interest rate has stayed the same, in what year did his balance hit $3300, according to the rule of 72?
Mathematics
2 answers:
storchak [24]4 years ago
8 0
1990 + 11 = 2001 this would give you the answer of 2001
9966 [12]4 years ago
6 0

Answer:

In 2001 years hit $3300

Step-by-step explanation:

On January 1,1990

Emilio deposited $1650 into saving account paying 6.2% interest compounded monthly.

Rule of 72

\dfrac{72}{Rate}=\text{Time for investment to double}

Rate = 6.3%

\text{Time for investment to double}=\frac{72}{6.3}=11.61

In 11.61 years amount hit $3300 into account.

Reference year was 1990. After 11 years hit $3300

Therefore, 1990 + 11 = 2001

At t=0 , January 1, 1990

At t=11.61, July 10, 2001

Thus, In 2001 years Emilio hit $3300 into account.

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