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3 years ago

Find LN, given that M lies between L and N, LM = 22 and MN = 6

Mathematics

1 answer:

nika2105 [10]3 years ago

4 0

Answer:

LN=28

Step-by-step explanation:

If the distance between L and M is 22 and the distance between M and N is 6, and M is between L and N, you would add 22+6 and get 28

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Evaluate and simplify if needed. Marking brainliest!!!! :))

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2 years ago

1/4(m 12)=-3/4 m+3 A 15 B 6 C 0 D-9

Marta_Voda [28]

Answer:

Step-by-step explanation:

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3 years ago

A survey of statistics students who had completed BUS 203 revealed that 70% sought additional help at the ICC Learning Lab, whil

Musya8 [376]

Answer:

a) P(NP/L) = 0.1

b) P(P/L) = 0.9

c) P(P) = 0.666

d) P(L/P) = 0.945

e) P(NL U NP) = 0.37

Step-by-step explanation:

given that;

P = passing the course, NP = Not passing the course, L = Using lab, NL = not using Lab

P(L) = 70% = 0.7, P(NL) = 30% = 0.3

P(P/L) = 90% = 0.9

P(P/NL) = 12% = 0.12

the probability of not passing the course given that the student went to the Learning Lab

P(NP/L) = 1 - P(P/L)

P(NP/L) = 1 - 0.9

P(NP/L) = 0.1

the probability of using the Learning Lab and passing the course

P(P/L) = 0.9

the probability of passing the class

P(P) = P(P/L) * P(L) + P(P/NL) * P(NL)

= (0.9 * 0.7) + (0.12 * 0.3)

P(P) = 0.666

the probability that a student utilized the Learning Lab given the condition that the student passed the class

P(L/P) = [P(P/L) * P(L)] / P(P)

P(L/P) = (0.9 * 0.7) / 0.666 = 0.63/0.666

P(L/P) = 0.945

the probability of not using the Learning Lab or not passing the class

P(NL U NP) = P(NL) + P(NP) - P(NP n NL)

= 0.3 + 0.334 - (0.88 * 0.3 )

= 0.634 - 0.264

P(NL U NP) = 0.37

4 0

4 years ago

Help with this question, ASAP PLEASE!! SHOW YOUR WORK!!

r-ruslan [8.4K]

Simplest polynomial function is $x^4-x^3-11x^2+9x+18.$

Solution:

Given data:

Zeroes are 3i, –1, 2.

3i is a complex root of the function.

If 3i is a zero of the polynomial then –3i is also a zero of the polynomial.

Therefore zeroes are 3i, –3i –1, 2.

By factor theorem,

If a is zero of the function, then (x – a) is a factor of the polynomial.

So, the factors are (x – 3i), (x + 3i), (x + 1), (x –2).

On multiplying the factors, we get the polynomial.

$(x - 3i) (x + 3i) (x + 1) (x -2)$

$=(x^2+3ix-3ix+(3i)^2)(x^2-2x+x-2)$

$=(x^2-9)(x^2-x-2)$

Since the value of $i^2=-1$

$=x^2(x^2-x-2)-9(x^2-x-2)$

$=x^4-x^3-2x^2-9x^2+9x+18$

$=x^4-x^3-11x^2+9x+18$

Simplest polynomial function is $x^4-x^3-11x^2+9x+18.$

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3 years ago

EASY BRAINLIEST PLEASE HELP!!

Galina-37 [17]

Answer: B

Step-by-step explanation: its B

8 0

3 years ago

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