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3 years ago

NEDD HELP DUE IN A HOUR

Mathematics

1 answer:

rosijanka [135]3 years ago

8 0

I know this won't sound helpful, but search up the answers for ALL of them. And, obviously, do it QUICKLY!

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I AM BEGGING YOU PLEASE IF YOU HAVE A HEART AWNSER FOR 50 POINTS AND BRILLIANT!!!

dangina [55]

5. Yes 1,2, or 3 hours
6. No, because the distance will never change and there aren't multiple values
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8. Yes, yes or no (a person could be colorblind)
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4 0

3 years ago

Read 2 more answers

If there are more negative numbers in an equation will the answer be negative?

Free_Kalibri [48]

Answer:

Not Always

example:

Yes:

12 - 4 + 20 - 16 - 32

32 - 48 = -20

No:

23 - 8 + 21 - 7 + 2 - 6 = 25

5 0

4 years ago

Read 2 more answers

What are two equivalent equations???????????????????

Trava [24]

1+1 is equal to 3-1. 1+1=2. 3-1=2. 2=2

4 0

3 years ago

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Daniel wants to have a 90 average in his math class at the end of the year. He is trying to determine what he needs to get on hi

morpeh [17]

Exam + Tests + Quizzes + HW + Projects = 90

Exam = 10% * grade (x) = 0.1 * x

Tests = 50% * 85 = 0.5 * 85 = 42.5

Quizzes = 15% * 95 = 0.15 * 95 = 14.25

HW = 15% * 98 = 0.15 * 98 = 14.7

Projects = 10% * 92 = 0.1 * 92 = 9.2

Exam + Tests + Quizzes + HW + Projects = 90

(0.1 * x) + 42.5 + 14.25 + 14.7 + 9.2 = 90

(0.1 * x) + 80.65 = 90 (subtract 80.65 from each side)

(0.1 * x) = 9.35 (divide 0.1 from each side)

(0.1 * x)/0.1 = 9.35/0.1

x = 0.935

The answer is 93.5%

4 0

3 years ago

Read 2 more answers

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

Kruka [31]

Answer:

$6.76-2.01\frac{2.55}{\sqrt{50}}=6.03$

$6.76+2.01\frac{2.55}{\sqrt{50}}=7.49$

The 95% confidence interval would be given by (6.03;7.49)

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=50 represent the sample size

Solution

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We can calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=6.76$

The sample deviation calculated $s=2.55$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

We assume a standard confidence level of 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$6.76-2.01\frac{2.55}{\sqrt{50}}=6.03$

$6.76+2.01\frac{2.55}{\sqrt{50}}=7.49$

The 95% confidence interval would be given by (6.03;7.49)

3 0

4 years ago