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3 years ago

How many feet are in a mile?

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

I think the answer is 5,280 I hope that helps! let me know if I was right please and thank you!

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I just need to know if these are parallel please,,,

Nataly_w [17]

These are parallel !

4 0

3 years ago

Read 2 more answers

1, 4, 9, 16, 25, ______, ______, ______

rosijanka [135]

The answer is 36 , 49 , & 64 .

8 0

3 years ago

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago

Translate the sentence into an inequality. The sum of 4 and y is less than 15.

bulgar [2K]

I believe the answer would be: 4+y<15

5 0

3 years ago

Hey yall,

lapo4ka [179]

Answer:

Step-by-step explanation:

pls mark brainliest

4 0

3 years ago