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3 years ago

The 5 in 6.052 has 1/10 the value of the 5 in ? Please explain

1 answer:

6 0

The tenths place, starting from the right, it gets higher going to the left. so the tenths place is only ten times greater than it.

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5) Allison plays a card game. She picks a card at random. Then without putting

SashulF [63]

Answer:

1/51

Step-by-step explanation:

3 0

3 years ago

Which set of ordered pairs does not represent a function

Alex Ar [27]

<h3>Answer:</h3>

The Second one {(-8,-7), (4,-2), (2,9), (-8,8)}

<h3 /><h3>Step-by-step explanation:</h3>

A function only gives ONE out put for a given value. But the second set has two outputs if we input -8, it gives you -7 and 8 so this must not be a function.

6 0

3 years ago

Read 2 more answers

What is m angle A?<br><br> ____degrees

Serggg [28]

Angle A is 10 degrees because you need to subtract 43 by 35 and u get 8 then u subtract 18 by 8.

Glad could help

8 0

3 years ago

Read 2 more answers

Ax+bx-c=0 x= _/(a __)

Ulleksa [173]

Ax+bx−c=0

Step 1: Add c to both sides.

ax+bx−c+c=0+c

ax+bx=c

Step 2: Factor out variable x.

x(a+b)=c

Step 3: Divide both sides by a+b.

x(a+b)a+b=ca+b

x=ca+b

4 0

3 years ago

Read 2 more answers

A simple random sample of 100 observations was taken from a large population. The sample mean and the standard deviation were de

olga2289 [7]

Answer:

Se=1.2

Step-by-step explanation:

The standard error is the standard deviation of a sample population. "It measures the accuracy with which a sample represents a population".

The central limit theorem (CLT) states "that the distribution of sample means approximates a normal distribution, as the sample size becomes larger, assuming that all samples are identical in size, and regardless of the population distribution shape"

The sample mean is defined as:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

And the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

Let X denotes the random variable that measures the particular characteristic of interest. Let, X1, X2, …, Xn be the values of the random variable for the n units of the sample.

As the sample size is large,(>30) it can be assumed that the distribution is normal. The standard error of the sample mean X bar is given by:

$Se=\frac{\sigma}{\sqrt{n}}$

If we replace the values given we have:

$Se=\frac{12}{\sqrt{100}}=1.2$

So then the distribution for the sample mean $\bar X$ is:

$\bar X \sim N(\mu=80,Se=1.2)$

5 0

3 years ago