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Paul [167]
3 years ago
14

The 5 in 6.052 has 1/10 the value of the 5 in ? Please explain

Mathematics
1 answer:
zepelin [54]3 years ago
6 0
The tenths place, starting from the right, it gets higher going to the left. so the tenths place is only ten times greater than it.
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Why you do not have to do any computing or math do solve 15 x 0 x (13 + 7)? Explain.
kozerog [31]

Answer:

because when you do 15*0 it =0 so anything else multiplied by 0 is 0

Step-by-step explanation:

6 0
3 years ago
please help me, i only get 2 chances to answer, and this is my last change, and i need help with math so bad
likoan [24]
67 percent
Which is 99000 x .67
6 0
3 years ago
Find
Sedaia [141]

Answer:

The amount of steel used = 94.38 m^{2}

Step-by-step explanation:

Height of the tank = 4.5 m.

Diameter of the tank = 4.2 m.

But,

radius = \frac{diameter}{2}

           = \frac{4.2}{2}

radius  = 2.1 m

Total surface area of a cylinder = 2\pirh + 2\pir^{2}

                                      = 2\pir(r + h)

                                      = 2 x \frac{22}{7} x 2.1 (2.1 + 4.5)

                                      = 44 x 0.3 (6.6)

                                      = 87.12

Total surface area of a cylinder = 87.12 m^{2}

Since \frac{1}{12} of the steel was wasted, then;

\frac{1}{12} x 87.12 = 7.26 m^{2}

Actual area of steel sheet used = 87.12 + 7.26

                                                     = 94.38 m^{2}

Thus, 94.38 m^{2} of steel was used in making the tank.

4 0
3 years ago
Find the reference angle given: t= -5π/3.
Elina [12.6K]

Answer:

The reference angle is \frac{\pi}{3}

Step-by-step explanation:

The given angle is t=-\frac{5\pi}{3}

The reference angle is the acute angle, that a given angle  makes with the x-axis.

First let us make a sketch of the given angle. <em>See diagram in attachment.</em>

Let \theta be the reference angle of  t=-\frac{5\pi}{3}


Then, from the diagram, we need to subtract \theta from -\frac{5\pi}{3} to get to -2\pi.


We can therefore write the following equation and solve for \theta.


\Rightarrow -\frac{5\pi}{3}-\theta=-2\pi


We group like terms to get,

\Rightarrow -\theta=-2\pi +\frac{5\pi}{3}

We collect LCM to get,

\Rightarrow -\theta=\frac{-6\pi+5\pi}{3}

We simplify to get,

\Rightarrow -\theta=-\frac{\pi}{3}

We divide through by -1

\theta=\frac{\pi}{3} to get,

The correct answer is D.







4 0
3 years ago
Which expression is equivalent to
lutik1710 [3]

Answer:

\frac{\sqrt[4]{3x^2} }{2y}

Step-by-step explanation:

We can simplify the expression under the root first.

Remember to use  \frac{a^x}{a^y}=a^{x-y}

Thus, we have:

\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}

We know 4th root can be written as "to the power 1/4th". Then we can use the property  (ab)^{x}=a^x b^x

<em>So we have:</em>

<em>\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}</em>

<em />

<em>Option D is right.</em>

8 0
3 years ago
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