All categories

3 years ago

Which of the following solution sets is all real numbers? Ixl >-2 Ixl <-2 Ixl = -2

Mathematics

2 answers:

Lisa [10]3 years ago

6 0

The first one, |x|>-2

Alekssandra [29.7K]3 years ago

3 0

Answer

Ixl >-2

Step-by-step explanation:

Ixl >-2 it would be this cause the unknown number was positive number. Positive was bigger than negative.

Ixl <-2 it can’t -2 cause the unknown number was positive

Ixl = -2 it can’t be equal cause the number was unknown and it wasn’t negative

I hope I can help you

I wish you a open path to your bright future.

You might be interested in

What is the approximate volume of a cone with a height of 6 mm and radius of 18 mm? Use 3.14 to approximate pi, and express your

leva [86]

Volume = 1/3×π×182×6 = <span>2035.7520395262 millimeters<span>3</span></span>

7 0

4 years ago

The diameter of a circle is 3.2 meters. Which is the circumference of the circle rounded to the nearest hundredth of a meter?

Paraphin [41]

Answer:

10.05 meters

Step-by-step explanation:

If the diameter is 3.2 meters, then the radius is 1.6 meters.

Use the circumference formula, C = 2 $\pi$ r, and solve for C

C = 2 $\pi$ r

C = 2 $\pi$ (1.6)

C = 3.2 $\pi$

C = 10.05

So, to the nearest hundredth of a meter, the circumference is 10.05 meters

4 0

2 years ago

Victoria has $2.90 in quarters, dimes and nickels. The numbers of nickels is one more than six times the number of quarters, and

maria [59]

Answer:

Step-by-step explanation:

She has 290 cents.

Nickels: 6x+1

Quarters: x

Dimes: 4x

Now that we've converted it algebraically, we can add them

6x+1 + x + 4x = 11x+1 = 290

11x = 289

x = 289/11

let me know if incorrect, i will fix

8 0

3 years ago

A____ is a fixed position in space and has no dimensions or size. hins

amid [387]

Answer:

Point

Step-by-step explanation:

This is the definition of a point.

A "point" is a fixed position in space and has no dimensions or size.

Cheers.

6 0

3 years ago

Read 2 more answers

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$

2. Since

$G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x)$ the function is neither even nor odd.

3. The domain is $x\in (-\infty,\infty),$ the range is $y\in (-\infty,\infty).$

8 0

3 years ago

Read 2 more answers