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2 years ago

Which of the following solution sets is all real numbers? Ixl >-2 Ixl <-2 Ixl = -2

Mathematics

2 answers:

Lisa [10]2 years ago

6 0

The first one, |x|>-2

Alekssandra [29.7K]2 years ago

3 0

Answer

Ixl >-2

Step-by-step explanation:

Ixl >-2 it would be this cause the unknown number was positive number. Positive was bigger than negative.

Ixl <-2 it can’t -2 cause the unknown number was positive

Ixl = -2 it can’t be equal cause the number was unknown and it wasn’t negative

I hope I can help you

I wish you a open path to your bright future.

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7. An aquarium is shown below. The

Mnenie [13.5K]

Answer:

1920 in³

Step-by-step explanation:

The volume of the water can be gotten by calculation the volume of the aquarium it fills/occupies.

Since the water fills to exactly three inches below the top of the aquarium, hence the height of the water in the aquarium is given as:

height of water = 13 in - 3 in = 10 in

Therefore the volume of the water in the tank is given by the formula:

Volume of water = height of water * breadth of tank * length of tank

Volume of water = 10 in * 8 in * 24 in = 1920 in³

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2 years ago

The parabola y=x² is shifted to the right 8 units. What is the equation to the new parabola

JulijaS [17]

The new equation is

<em>Y = (x-8)² </em>.

The other way to write it is like this: (you might not recognize it in this form)

Y = x² - 16x + 64

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3 years ago

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xxTIMURxx [149]

1583 because that’s the year that the they created that math problem

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2 years ago

Read 2 more answers

Solve the equation: \frac{2}{3}t=\frac{5}{9} (hint: reciprocal)

Aleks04 [339]

Given:

$\frac{2}{3}t=\frac{5}{9}$ $\text{ We know that the reciprocal of }\frac{2}{3}\text{ is }\frac{3}{2}\text{.}$

Multiply both sides by 3/2, we get

$\frac{3}{2}\times\frac{2}{3}t=\frac{3}{2}\times\frac{5}{9}$

Cancel out the common multiples, we get

$t=\frac{1}{2}\times\frac{5}{3}$

$t=\frac{1\times5}{2\times3}$

$t=\frac{5}{6}$

The solution of the given equation is

$t=\frac{5}{6}$

$t=0.8333.$

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jeka57 [31]

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3 years ago