To find the Least Common Multiple you first have to write down multiples of each number until one same multiple occurs in both lists. Once you find that multiple you can circle it to use it in your answer.
To find the greatest common factor you just have you list all the factors of that number and the other's too. Then you circle the largest factor that occurs in both lists.
Answer:
The value is ![E(x) = 1.25](https://tex.z-dn.net/?f=E%28x%29%20%3D%20%201.25%20)
Step-by-step explanation:
From the question we are told that
The number of cans is n = 4
The number of can that are empty is N = 3
The number of can filled with water is k = 1
The number number of sets of cans is w = 5
Generally probability of detecting the correct can is mathematically represented as
![p = \frac{k}{n}](https://tex.z-dn.net/?f=p%20%20%3D%20%20%5Cfrac%7Bk%7D%7Bn%7D)
=> ![p = \frac{1}{4}](https://tex.z-dn.net/?f=p%20%20%3D%20%20%5Cfrac%7B1%7D%7B4%7D)
=> ![p = 0.25](https://tex.z-dn.net/?f=p%20%20%3D%200.25)
Generally probability of not detecting the correct can is mathematically represented as
![q = 1- p](https://tex.z-dn.net/?f=q%20%3D%20%201-%20p)
![q = 1- 0.25](https://tex.z-dn.net/?f=q%20%3D%20%201-%200.25)
![q = 0.75](https://tex.z-dn.net/?f=q%20%3D%200.75)
Generally the number of cans expected of the farmer to correctly identify by chance is mathematically represented as
![E(x) = w * p](https://tex.z-dn.net/?f=E%28x%29%20%3D%20%20w%20%20%2A%20%20p)
=> ![E(x) = 5 * 0.75](https://tex.z-dn.net/?f=E%28x%29%20%3D%20%205%20%20%2A%200.75%20)
=> ![E(x) = 1.25](https://tex.z-dn.net/?f=E%28x%29%20%3D%20%201.25%20)
Answer:
$74.68
Step-by-step explanation:
Convert the percent to a decimal.
4% = 0.04
Multiply his income by the percentage to find the tax.
$1,867 × 0.04 = $74.68
He can expect to pay $74.68.
Experimental probability = 1/5
Theoretical probability = 1/4
note: 1/5 = 0.2 and 1/4 = 0.25
=============================================
How I got those values:
We have 12 hearts out of 60 cards total in our simulation or experiment. So 12/60 = (12*1)/(12*5) = 1/5 is the experimental probability. In the simulation, 1 in 5 cards were a heart.
Theoretically it should be 1 in 4, or 1/4, since we have 13 hearts out of 52 total leading to 13/52 = (13*1)/(13*4) = 1/4. This makes sense because there are four suits and each suit is equally likely.
The experimental probability and theoretical probability values are not likely to line up perfectly. However they should be fairly close assuming that you're working with a fair standard deck. The more simulations you perform, the closer the experimental probability is likely to approach the theoretical one.
For example, let's say you flip a coin 20 times and get 8 heads. We see that 8/20 = 0.40 is close to 0.50 which is the theoretical probability of getting heads. If you flip that same coin 100 times and get 46 heads, then 46/100 = 0.46 is the experimental probability which is close to 0.50, and that probability is likely to get closer if you flipped it say 1000 times or 10000 times.
In short, the experimental probability is what you observe when you do the experiment (or simulation). So it's actually pulling the cards out and writing down your results. Contrast with a theoretical probability is where you guess beforehand what the result might be based on assumptions. One such assumption being each card is equally likely.
Answer:
4.5 sq. units.
Step-by-step explanation:
The given curve is ![y = (3x)^{\frac{1}{2} }](https://tex.z-dn.net/?f=y%20%3D%20%283x%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D)
⇒
...... (1)
This curve passes through (0,0) point.
Now, the straight line is y = 3x - 6 ....... (2)
Now, solving (1) and (2) we get,
![y^{2} - y - 6 = 0](https://tex.z-dn.net/?f=y%5E%7B2%7D%20-%20y%20-%206%20%3D%200)
⇒ (y - 3)(y + 2) = 0
⇒ y = 3 or y = -2
We will consider y = 3.
Now, y = 3x - 6 has zero at x = 2.
Therefor, the required are = ![\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E3_0%20%7B%283x%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%20-%20%5Cint%5Climits%5E3_2%20%7B%283x%20-%206%29%7D%20%5C%2C%20dx)
= ![\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%5B%7B%5Cfrac%7Bx%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%7D%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%7D%5D%5E%7B3%7D%20_%7B0%7D%20-%20%5B%5Cfrac%7B3x%5E%7B2%7D%20%7D%7B2%7D%20-%206x%20%5D%5E%7B3%7D%20_%7B2%7D)
= ![[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Csqrt%7B3%7D%5Ctimes%202%20%5Ctimes%203%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%7D%7B3%7D%5D%20-%20%5B13.5%20-%2018%20-%206%20%2B%2012%5D)
= 6 - 1.5
= 4.5 sq. units. (Answer)