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Fudgin [204]
3 years ago
11

I attached a pic please help

Mathematics
1 answer:
umka2103 [35]3 years ago
6 0
Function P: y intercept of 5 (0,5), no slope
Function Q: y=- \frac{1}{3} x+4, m=- \frac{1}{3}

A: Both functions do NOT have the same slope.
B: Both functions do NOT have negative slope.
C: Functions will NOT have same input when y=0
D. The functions will have different outputs when x=0 (Function P: (0, 5) and Function Q: (0, 4)
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6/8 divide by 8/12<br> A. 9/2<br><br><br> B. 8/9<br><br><br> C. 9/8<br><br><br> D. 9/32
Musya8 [376]

Answer:

C. 9/8

Step-by-step explanation:

\frac{6}{8}  \div  \frac{8}{12}

Use KCF which means Keep the first fraction, Change the second fraction by flipping it and change the division sign to a multiplication symbol:

\frac{6}{8}  \times  \frac{12}{8}

multiply the numerator together:

6 × 12 = 72

multiply the denominator together:

8 × 8 = 64

now the fraction is:

\frac{72}{64}

simplify further by dividing both numbers by 8:

72 ÷ 8 = 9

64 ÷ 8 = 8

so the fraction is 9/8

3 0
2 years ago
High school football team had the best game of the season they scored eight touchdowns (seven points each) and three field goals
Alla [95]

Answer:

65 points in all

Step-by-step explanation:

3 x 3 = 9

7 x 8 = 56

56 + 9 = 65

:))

6 0
3 years ago
Help I don’t understand the concept
kvasek [131]

Answer:

C. No, because one x-value corresponds to two different y-values

Step-by-step explanation:

An x-value cannot have two y-values. Hope this helps!

6 0
3 years ago
Read 2 more answers
Need pre-cal help. Will mark best answer brainliest
OlgaM077 [116]

so, let's keep in mind that

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}

so let's make a quick table of those solutions, say A, B, C solutions with x,y,z liters of acid, with an acidity of 0.25, 0.40 and 0.60 respectively.


\bf \begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ A&x&0.25&0.25x\\ B&y&0.40&0.4y\\ C&z&0.60&0.6z\\ \cline{2-4}&\\ mixture&78&0.45&35.1 \end{array} \\\\\\ \begin{cases} x+y+z=78\\ 0.25x+0.4y+0.6z=35.1 \end{cases}


we know she's using "z" liters and those are 3 times as much as "y" liters, so z = 3y.


\bf \begin{cases} x+y+3y=78\\ x+4y=78\\[-0.5em] \hrulefill\\ 0.25x+0.4y+0.6(3y)=35.1\\ 0.25x+0.4y=1.8y=35.1\\ 0.25x+2.2y=35.1 \end{cases}\implies \begin{cases} x+4y=78\\\\ 0.25x+2.2y=35.1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x+4y=78\implies \boxed{x}=78-4y \\\\\\ \stackrel{\textit{using substitution on the 2nd equation}}{0.25\left( \boxed{78-4y} \right)+2.2y=35.1}\implies 19.5-y+2.2y=35.1


\bf 1.2y=15.6\implies y=\cfrac{15.6}{1.2}\implies \blacktriangleright y=13 \blacktriangleleft \\\\\\ x=78-4y\implies x=78-4(13)\implies \blacktriangleright x=26 \blacktriangleleft \\\\\\ z=3y\implies z=3(13)\implies \blacktriangleright z=39 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{25\%}{26}\qquad \stackrel{40\%}{13}\qquad \stackrel{60\%}{39}~\hfill

5 0
3 years ago
Rewrite using a negative exponent. 5/x^2
SashulF [63]

Answer:

5x^-2 is rewritten as a negative exponent

4 0
3 years ago
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