Give the dimensions of two different rectangles that have the same area

Which group of ordered pairs are on the line given by the equation 5−2=6

Zolol [24]

Answer: (0,-3)

Explanation: use desmos.con it will help! :)

8 0

3 years ago

Twenty-seven is % of 60 help mee asap

jok3333 [9.3K]

Answer: The answer is: " 45 % " .

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→ " Twenty-seven is 45 % of 60. "

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Step-by-step explanation:

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The question asks:

" 27 is what % {percentage] of 60 " ? ;

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So: " 27 = (n/100) * 60 " ; Solve for "n" ;

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Method 1:

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→ (n/100) * 60 = 27 ;

Divide each side by 60 :

→ [ (n/100) * 60 ] / 60 = 27 /60 ;

to get:

→ (n/100) = 27/60 ;

Now: Cross-factor multiply:

→ 60n = (27)*(100) ;

to get:

→ 60n = 2700 ;

Divide each side by "60" ;

→ 60n = 2700/ 60 ;

to get: n = 45 ;

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→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2:

________________________________________________

The question asks:

" 27 is what % {percentage] of 60 " ?

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To solve this problem:

Rephrase this question as:

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" 27 is 60% of what number ? "

→ The answer will be the same!

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→ 27 = (60/100)* n ; Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→ 100 * 27 = 100 * [ (60/100)* n ] ;

to get:

→ 2700 = 60n ;

↔ 60n = 2700 ;

Divide Each Side of the equation by "60" ;

→ 60n/60 = 2700 / 60 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2: Variant 1 of 2:

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When we have:

→ 27 = (60/100)* n ; Solve for "n" ;

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Note that: "(60/100) = (60÷ 100) = (6 ÷ 10)" ; since: in "(60/100)" ; the "zero" from the "numerator" cancels out; And: the "last zero" in "100" — from the "denominator" cancels out; since we are dividing "each side" of the fraction by "10" ;

→ "(60÷10) / (600÷10)" = " 6/10 " ;

→ " (6/10)" ; that is; "six-tenths"} ;

→ can be represented by: " 0.6 " ;

→ {by convention; but specifically, here is the explanation} — as follows:

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→ "(6/10)" = " (6 ÷ 10) " ;

Note: When dividing a number by "10" ; we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".

Note: When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10". We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying; and to the left if we are dividing. In this case, we are dividing "6" by "10 " :

→ " 6 ÷ 10 = ? " ;

→ " 6. ÷ 10 = ? " ;

We take the: " 6. " ; and move the decimal point "one space backward [i.e. "to the left"]; since we are dividing by "10" ;

→ to get: " .6 " ; & we rewrite this value as "0.6" in a rewritten equation:

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So; we take our equation:

→ 27 = (60/100)*n ; And rewrite—substituting "0.6" for

"(60/100)"— as follows:

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→ 27 = (0.6)n ; ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

→ 10 * [ (0.6)n ] = 27 * 10 ;

to get:

→ 6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 6n / 6 = 270 / 6 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2 (variant 2 of 2):

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We have the equation: 27 = (60/100)* n ; Solve for "n" ;

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Note: From Method 2 (variant) 1 of 2— see above):

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Note: Refer to the point at which we have:

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→ " { (60÷10) / (600÷10)" = " (6/10) " ; that is; "six-tenths"} ;

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Note that the fraction— "(6/10)" ; can be further simplified:

→ "(6/10)" = "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ; with: "(3/5)" :

→ 27 = (3/5)* n ; Solve for "n" ;

↔ (3/5)* n = 27 ;

↔ (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→ 5* (3n/5) = 27 * 5 ;

to get:

→ 3n = 135 ;

Divide Each side of the equation by "3" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 3n / 3 = 135 / 3 ;

to get: n = 45 ;

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→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

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Hope this answer is helpful!

Wishing you the best in your academic endeavors

— and within the "Brainly" community!

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7 0

3 years ago

Read 2 more answers

There are 12 grams of sugar in 1⁄3 of a piece of candy. How much sugar is in 3⁄4 of a piece of candy?

lisov135 [29]

Answer:

27 grams of sugar

Step-by-step explanation:

If 1/3 candy contains 12 grams of sugar

Then 3/4 candy contains C grams of sugar

C= 3/4 * 12grams➗1/3=3*12*3grams➗4=108grams➗4=27 grams of sugar

4 0

3 years ago

In which quadrants do solutions for the inequality y is less than or equal to two sevenths times x plus 1 exist? i, iii, and iv

tigry1 [53]

The solutions will lie in all the four quadrants.

y≤2/7x+1

We have the following inequality:

y=2/7x+1

If x=0

y=2/7(0) +1

y=1

If y=0

x=-3.5

So the line passes through the points:

(0,1) and (-3.5,0)

To find the shaded region, let us take a point, namely, the origin and test it in the inequality:

y≤ 2/7x +1

0≤ 2/7(0) +1

0≤ 1 which is true

Since this is true, then the shaded region includes this point. This is shown below and as you can see the solutions exist in all four quadrants.

To learn more about Inequalities, visit brainly.com/question/12890742

#SPJ4

4 0

2 years ago

Need help in algebra fast Anything helps

alex41 [277]

Answer:

c

Step-by-step explanation:

For this question you can say d = 15 feet so we need the t then you can say :

15 = l 130 - 25t l ⇒ because of the absolute value you should say :

1) 130 - 25t = 15 ⇒ -25t = 15 - 130 ⇒ - 25t = -115 ⇒ t = 115/25 = 4.6 sec

2) 130 - 25t = - 15 ⇒ -25t = -15 - 130 ⇒ -25t = - 145 ⇒ t = 145/25 = 5.8 sec

so the answer is c :))

i hope this is helpful

7 0

3 years ago