Answer:
Simplified base would be 3∛4
Step-by-step explanation:
Given exponential function,
![f(x)=\frac{1}{4}(\sqrt[3]{108})^x](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B108%7D%29%5Ex)
Since, in an exponential function 
b is called base.
∵ 108 = 2 × 2 × 3 × 3 × 3,
Or 108 = 4 × 3³,
![\implies \sqrt[3]{108} = \sqrt[3]{4\times 3^3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7B108%7D%20%3D%20%5Csqrt%5B3%5D%7B4%5Ctimes%203%5E3%7D)
![\sqrt[3]{108}=\sqrt[3]{4}\times \sqrt[3](3^3)](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D%5Csqrt%5B3%5D%7B4%7D%5Ctimes%20%5Csqrt%5B3%5D%283%5E3%29)
( Using ![\sqrt[n]{ab}=\sqrt[n]{a}\times \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D)
)
![\sqrt[3]{108}=\sqrt[3]{4}\times (3^3)^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D%5Csqrt%5B3%5D%7B4%7D%5Ctimes%20%283%5E3%29%5E%5Cfrac%7B1%7D%7B3%7D)
![\sqrt[3]{108}=\sqrt[3]{4}\times 3^{3\times \frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D%5Csqrt%5B3%5D%7B4%7D%5Ctimes%203%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%7D)
( Using power of power property of exponent )
![\sqrt[3]{108}=3\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D3%5Csqrt%5B3%5D%7B4%7D)
Hence, the required simplified base would be 3∛4
i.e. SECOND option is correct.
Answer:
so if jake is 2 years younger and alex is 1 year older than james and james is twice the age so
and u gave a hint so amy is 9 and james is 19 alex is 18 and jake is 17
so 9+19+18+17 = 63
there u go
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
( 3 - 4 ) ( - 2 )
= ( - 1 ) ( - 2 )
= 2
Answer: (0,-10) and the transformation should be a reflection
Step-by-step explanation:
Answer:
4/15
Step-by-step explanation:
4/10*6/9
2/5*2/3
4/15
