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Katyanochek1 [597]
3 years ago
7

An orange is divided into 6 equal wedges.Jody eats 1 wedges.How much of the orange did Jody eat?

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0

Answer:

1/6..

Step-by-step explanation:


Simora [160]3 years ago
6 0

Answer:


Step-by-step explanation:

Answer: 1/6


Its either part of a 6th or, a 3rd


And since jody ate one wedge, that wont devide. So it must be 1/6.

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What is 1 2/3 - (-5 2/3)
arsen [322]

Answer:

the answer is 7.33

Step-by-step explanation:

I used a calculator

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2 years ago
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For which rational expression is 8 an excluded value ? check all that apply
denis23 [38]

<u>Answer:</u>

The correct answer options are C. \frac{x^2+5}{x-8} and D. \frac{x^2-x-56}{x^2-64}.

<u>Step-by-step explanation:</u>

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0

\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}

\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}

\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0

\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}

7 0
3 years ago
➥ The base of a parallelogram is thrice its height. If the area is 897 sq.cm. Find the base and height of the parallelogram.
IgorC [24]

Answer:

The height of parallelogram is 51.87 cm

Step-by-step explanation:

Let The height of a parallelogram = a cm

Then

The base of a parallelogram = 3a cm

So by the given condition

3a×a = 897

3a^2 = 897

a^2 = 897/3

a^2 = 299

a = 17.29

So the height of parallelogram = 3×17.29= 51.87 cm

6 0
3 years ago
Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x&lt;-36
Oliga [24]
X²+15x+36<0

at first solve quadratic equation

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x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

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 1 case)      x+12<0, and x+3>0,                                            
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(-∞, -12) and(-3,∞) gives empty set

or second case)  x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3)  they are crossing , so (-12, -3)  is a solution of this inequality


3 0
3 years ago
Answer (2 + 2) - 4 + 2
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