54 is the hypotenuse because it is the longest side. Square all of the sides. So 54^2=2916
51^2=2601
22^2=484
Now you have 2916=2601+484
Add the two and they will be greater than 2916. Because of that, you will have an acute triangle because 22^2+51^2>54^2
In short, its B
I’m pretty sure that it’s the third answer (q^12)! :)
Answer:
b
Step-by-step explanation:
the y axis is the axis going up and down, so the reflection would be on the other side of the axis.
Answer:
The camera had to cover the greatest angle is CAMERA 3 because it had the largest angle of 71.47°
Step-by-step explanation:
From the above question,
We have:
Camera 1 = Angle A
Camera 2= Angle B
Camera 3 = Angle C
A = 210ft
B = 234ft
C = 260ft
We need to find Angle A( angle of camera 1) using the cosine rule
A=(B² + C² - 2BCCosA)
210² = 234² + 260² - 2 × 234 × 260 × CosA
210² = 122356 - 121680CosA
Square both sides
210² = 122356 - 121680CosA
44100 = 122356 - 121680CosA
121680CosA = 122356 - 44100
121680CosA = 78256
Cos A = 78256/121680
Cos A = 0.6431295201
A = arc cos (0.6431295201)
A = 49.974422249°
Angle A approximately = 49.97°
Using the Sine rule to find the Angle B
A/Sine A = B/Sine B
210ft/Sine 49.97° = 234ft/Sine B
210ft × Sine B = 49.97° × 234ft
Sine B =( Sine 49.97° × 234ft)/210ft
B = arc sin (0.8532172354)
Angle B = 58.56334
Approximately = 58.56°
Angle C = 180 - (49.97 + 58.56)°
Angle C = 71.47°
Therefore, the camera had to cover the greatest angle is Camera 3 because it had the largest angle of 71.47°
