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olga nikolaevna [1]
2 years ago
14

Line v has a slope of –8/7. Line W is perpendicular to V. What is the slope of line w?

Mathematics
1 answer:
blondinia [14]2 years ago
7 0

Answer:

\frac{7}{8}

Step-by-step explanation:

The slope of a perpendicular line is opposite and reciprocal to the original slope. Flip the fraction and change the sign, and you're all set!

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Easy so just Take 4.50 and I said by 1.50 which one you're going to get three more bags of three need times it by 108÷10 and then that will just be one box and then all you have to do is just find the other boxes with that number so
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Choose the correct discriminant, then
irina [24]

Answer:

3

Step-by-step explanation:

Order of Operations; PEMDAS  

Parentheses  

Exponents  

Multiplication & Division (Left to Right) (ex: 10x2÷5) You would do whatever comes left for Multiplication or Division.  

Addition & Subtraction (Left to Right) (ex: 10-2+5) You would do whatever comes left for Addition & Subtraction.

3x+6 =

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Solve the equation using square roots. (X+3)^2=0
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Answer:

x=3

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(x−3)^2=0

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x−3=0

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x=3

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2 years ago
Nicole used 24 pieces of fruit if 1/6 of them were peaches how many peaches in all did Janeen and Nicole use to make their fruit
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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

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3 years ago
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