Answer:
Time spent rowing down stream 
Speed of boat in still water 
Step-by-step explanation:
Let speed of boat in still water be 
Speed of current 
Speed of boat down stream = 
Distance rowed down stream = 2400 m
Time spent rowing down stream =
= 
Speed of boat up stream = 
Distance rowed up stream = 
Time spent rowing up stream = 
We know that,
So,

Cross multiplying

Dividing both sides by 



Adding 60 to both sides.


Subtracting both sides by 


Dividing both sides by 5.

∴ 
Speed of boat in still water 
Time spent rowing down stream =
Well, following the order of PEMDAS, I got choice B. 52
For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.
Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.
In this case, you square the number 5, which gives you F(5)=2(25)+2
After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.
Finally, you add them, which results in F=52.
By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.
Anyway, hope this helped! :-)
Answer:






Step-by-step explanation:
Given the congruence statement ∆CGI
∆MPR, it follows that the corresponding sides of both ∆s are equal, as well as the corresponding vertices or angles. It implies that ∆CGI and ∆MPR are of the same shape and size.
✅Thus, the 6 pairs of the corresponding congruent parts of ∆CGI and ∆MPR are:






Answer:
1.5 units squared
Step-by-step explanation:
Area of a Triangle formula: A = 1/2bh
Pythagorean Theorem: a² + b² = c²
Since you are missing the <em>h </em>to find the area of the triangle, you must use Pythagorean to find the 3rd missing side (it is a right triangle so you can use Pythagorean).
Step 1: Use Pythagorean
2.5² = 1.5² + b²
4 = b²
b = 2
Step 2: Switch variables
b (from Pythagorean) = h (height for Area)
Step 3: Solve for Area
A = 1/2(1.5)(2)
A = 1.5
And you have your final answer.