The probability of drawing two blue marbles if the first marble is not replaced is 1/5
<h3>How to determine the probabilities?</h3>
<u>The probability of tossing a head and drawing a red marble</u>
The given parameters are:
White = 1
Blue =3
Red = 2
Total = 6
The probability of a head is
P(Head)= 1/2
The probability of drawing a red marble is
P(Red)= 2/6 = 1/3
The required probability is
P = P(Head) * P(Red)
This gives
P = 1/2 * 1/3
P =1/6
<u>The probability of drawing two blue marbles if the first marble is not replaced.</u>
Here, we have:
P(B1) = 3/6 = 1/2
P(B2) = 2/5
The required probability is
P = P(B1) * P(B2)
This gives
P = 1/2 * 2/5
P =1/5
Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5
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Answer:
The Least Common Denominator of 3/4, 4/5 and 2/3
Would be,
4 × 5 × 3 = 60
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>60</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>L.C.D</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>3</u></em><em><u>/</u></em><em><u>4</u></em><em><u>,</u></em><em><u> </u></em><em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u>/</u></em><em><u>3</u></em>
we have that
the total cost is

In this equation the term 30h represent the cost due to h hours at at unit of 30
and the term 0.040(30h) is equal to calculate the 4% of (30h)
so
in this problem the tax rate is equal to 4%
therefore
<u>the answer is</u>
The term 0.040(30h) represents the amount of tax she must pay
I know this one! 954 divided by 6 equals to 154
-6(1+7x)+7(1+6x)=-2
This is False.
Use distributive property:
-6 -42x + 7 +42x = -2
Combine like terms to get:
1 = -2
Since 1 is not -2, it is false.