Question

POSSIBLE OUTCOMES!!!

Answer 1

The probability of drawing two blue marbles if the first marble is not replaced is 1/5

How to determine the probabilities?

The probability of tossing a head and drawing a red marble

The given parameters are:

White = 1

Blue =3

Red = 2

Total = 6

The probability of a head is

P(Head)= 1/2

The probability of drawing a red marble is

P(Red)= 2/6 = 1/3

The required probability is

P = P(Head) * P(Red)

This gives

P = 1/2 * 1/3

P =1/6

The probability of drawing two blue marbles if the first marble is not replaced.

Here, we have:

P(B1) = 3/6 = 1/2

P(B2) = 2/5

The required probability is

P = P(B1) * P(B2)

This gives

P = 1/2 * 2/5

P =1/5

Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5

Read more about probability at:

brainly.com/question/24756209

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