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balu736 [363]
2 years ago
7

Figure ABCD is a trapezoid find the Value of x

Mathematics
2 answers:
denpristay [2]2 years ago
4 0

Answer:

<em>The value of x is 4.</em>

Step-by-step explanation:

Figure ABCD is a trapezoid, in which AD and BC are parallel sides.

Given that, AD= 3x+10 and BC=2x

Now, <u>the length of the median</u>  = \frac{1}{2}(AD+BC) , <u>which is given as</u>  15.

So, the equation will be......

\frac{1}{2}[(3x+10)+2x]=15\\ \\ \frac{1}{2}(5x+10)=15\\ \\ 5x+10=2(15)\\ \\ 5x+10=30\\ \\ 5x=30-10\\ \\ 5x=20\\ \\ x=\frac{20}{5}=4

So, the value of x is 4.

valina [46]2 years ago
3 0

Answer:

The value of x is 4

Step-by-step explanation:

we know that

in this problem

\frac{1}{2}(2x+(3x+10))=15

solve for x

\frac{1}{2}(5x+10)=15

(5x+10)=30

5x=30-10

x=20/5=4

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