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3 years ago

Figure ABCD is a trapezoid find the Value of x

Mathematics

2 answers:

denpristay [2]3 years ago

4 0

Answer:

The value of $x$ is 4.

Step-by-step explanation:

Figure $ABCD$ is a trapezoid, in which $AD$ and $BC$ are parallel sides.

Given that, $AD= 3x+10$ and $BC=2x$

Now, the length of the median $= \frac{1}{2}(AD+BC)$ , which is given as $15.$

So, the equation will be......

$\frac{1}{2}[(3x+10)+2x]=15\\ \\ \frac{1}{2}(5x+10)=15\\ \\ 5x+10=2(15)\\ \\ 5x+10=30\\ \\ 5x=30-10\\ \\ 5x=20\\ \\ x=\frac{20}{5}=4$

So, the value of $x$ is 4.

valina [46]3 years ago

3 0

Answer:

The value of x is 4

Step-by-step explanation:

we know that

in this problem

$\frac{1}{2}(2x+(3x+10))=15$

solve for x

$\frac{1}{2}(5x+10)=15$

$(5x+10)=30$

$5x=30-10$

$x=20/5=4$

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Find the degree of the polynomial b5 + 2b3 + 7.

scoray [572]

Answer:

Step-by-step explanation:

b^5 + 2b^3 + 7

Here,

degrees are 5 and 3.

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Out of 3 and 5

5 is the highest / greatest number.

Hence,

the degree of the given polynomial is 5.

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2 years ago

How do i simplify this

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3 years ago

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

Which of these is an open sentence?

Anna007 [38]

B because k is not a specified number

3 0

3 years ago

Read 2 more answers

Which of the following is the graph of 2x+3y=6

Bond [772]

Taking point (0,-2) of graph one and replacing in the equation;

2x+3y=6

2(0)+3(-2)=6

-6=6

So graph isn't the required graph.

Taking point (0,2) of graph 2;

2x+3y=6

2(0)+3(2)=6

6=6

So, graph 2 is the required graph.

8 0

3 years ago

Read 2 more answers