Question

Figure ABCD is a trapezoid find the Value of x

Answer 1

Answer:

The value of $x$ is 4.

Step-by-step explanation:

Figure $ABCD$ is a trapezoid, in which $AD$ and $BC$ are parallel sides.

Given that, $AD= 3x+10$ and $BC=2x$

Now, the length of the median  $= \frac{1}{2}(AD+BC)$ , which is given as  $15.$

So, the equation will be......

$\frac{1}{2}[(3x+10)+2x]=15\\ \\ \frac{1}{2}(5x+10)=15\\ \\ 5x+10=2(15)\\ \\ 5x+10=30\\ \\ 5x=30-10\\ \\ 5x=20\\ \\ x=\frac{20}{5}=4$

So, the value of $x$ is 4.

Answer 2

Answer:

The value of x is 4

Step-by-step explanation:

we know that

in this problem

$\frac{1}{2}(2x+(3x+10))=15$

solve for x

$\frac{1}{2}(5x+10)=15$

$(5x+10)=30$

$5x=30-10$

$x=20/5=4$