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Alenkasestr [34]
3 years ago
13

If 'a' is a number lying between 0 and 1. then which of the following is in increasing order? a) a², a, √a b) a √a ,a² c) a²,√a,

a d) a, a², √a ​
Mathematics
2 answers:
viktelen [127]3 years ago
5 0

Step-by-step explanation:

None of these,

a(under root),a, a(square)

this is the correct answer

Vlad1618 [11]3 years ago
3 0

Hello,

0\leq a\leq 1 \Longrightarrow 0*a\leq a*a\leq 1*a \Longrightarrow 0 \leq a^2 \leq a\\\\0\leq a^2\leq a \Longrightarrow \sqrt{0} \leq \sqrt{a^2}  \leq \sqrt{a} \\\\The\ function\ y=x^2\ is\ increasing\\\\Answer A\\\\ex: a=0.5 \\\\a^2=0.25\\\\\sqrt{a}=\dfrac{\sqrt{2}}{2}\approx{0.7071...}\\\\and\ 0.25\leq 0.5 \leq  0.7071...

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A can of soda weighs 336 grams. find the weight in kilograms of 20 cans.
jolli1 [7]
20 cans in kilograms = 336 grams * 20 cans / 1000 = 6.72 kg
8 0
3 years ago
A. 55<br> b. 70<br> c. 110<br> d. 125
morpeh [17]

Answer:

b

Step-by-step explanation:

7 0
2 years ago
4th grade math. Help?!
viva [34]

Answer: Well... does it give you the approximate length or actual length of the butterfly? If so, you would take that length and multiply it by 5. That would give you the length of the 5 butterfly lined up together.

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Take that and multiply it by five to get the length of the 5 butterflies.



7 0
3 years ago
Read 2 more answers
A rectangular box without a lid is to be made from 48 m2 of cardboard. Find the maximum volume of such a box. SOLUTION We let x,
tatiyna

Answer:

The maximum volume of such box is 32m^3

V = x×y×z = 32 m^3

Step-by-step explanation:

Given;

Total surface area S = 48m^2

Volume of a rectangular box V = length×width×height

V = xyz ......1

Total surface area of a rectangular box without a lid is

S = xy + 2xz + 2yz = 48 .....2

To be able to maximize the volume, we need to reduce the number of variables.

Let assume the rectangular box has a square base,that means; length = width

x = y

Substituting y with x in equation 1 and 2;

V = x^2(z) ....3

x^2 + 4xz = 48 .....4

Making z the subject of formula in equation 4

4xz = 48 - x^2

z = (48 - x^2)/4x .......5

To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3

V = x^2 × (48 - x^2)/4x

V = (48x - x^3)/4

differentiating V with respect to x;

V' = (48 - 3x^2)/4

At the maximum point V' = 0

V' = (48 - 3x^2)/4 = 0

Solving for x;

3x^2 = 48

x = √(48/3)

x = √(16)

x = 4

Since x = y

y = 4

From equation 5;

z = (48 - x^2)/4x

z = (48 - 4^2)/4(4)

z = 32/16

z = 2

The maximum volume can be derived by substituting x,y,z into equation 1;

V = xyz = 4×4×2 = 32 m^3

7 0
3 years ago
Someone please help! I have spent lots of time on this and I’m still confused
vfiekz [6]

Answer:

its the 3rd choice.

Step-by-step explanation:

Firstly, we find angle BDC (180-90-30=60)

Now that we found it we can use the sine rule to find DB (which i put as an x), which is sin60/14=sin30/x, by cross multiplication, we find that its equal to a decimal number, i will use its root version to this easier, its equal to 14sqrt3/3 inches.

And now we use the pythagorean theorem to find DC, we find that it is equal to 28sqrt3/3

Now, we find angle BAC (180-90-(30+15)=45)

Again, we use the sine rule to find AB (whom i will refer to as x and from whom we will subtract DB to find the length of AD), so we cross multiply in sin45/14=sin(30+15)/x, it is equal to 14.

So since AB-DC=AD

14-(14sqrt3/3)= 5.917096231 (and we ound that to a 5.9)

3 0
2 years ago
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