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3 years ago

Homework Worksheet: 3.2 Day 1 - Slope

Mathematics

1 answer:

madreJ [45]3 years ago

7 0

Answer:

1) zero

2) undefined

3) negative

4) positive

5) negative y= -30x+342

hope this helps;)

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Can someone help me out with the answer please

dmitriy555 [2]

Answer:

I think it is D. Becuase you have to simplify the numarater then the demonater.

5 0

3 years ago

What is the total cost or sale price to the nearest cent 20$ haircut; 15% tip

wel

$20 hai
The answer is $23.00

3 0

3 years ago

Calculate S30 for the arithmetic sequence defined by {an}={3.1n-2}

timurjin [86]

Answer:

c) 1,381.5.

Step-by-step explanation:

First term = 3.1 *1 - 2 = 1.1

2nd term = 3.1*2 - 2 = 4.2

3rd term = 3.1*3 - 2 = 7.3

so the common difference d = 3.1.

S30 = (30/2) [ 2* 1.1 + (30-1) * 3.1)]

= 1,381.5.

3 0

3 years ago

In triangle ABC, AC =24, the measure of angle A = 30 degree , and the measure of angle B = 45 degree . Find the area of this tri

andriy [413]

Answer:

142.932

Step-by-step explanation:

given that in triangle ABC, AC =24

Angle A = 30 and Angle B =45

If we draw altitude from C, we get

h = 24sin 30 = 12

Since BC = h (45, 45,90 triangle)

BC=12

By sine formula for triangle

$\frac{12}{sin30} =\frac{AB}{sin(180-45-30)} \\AB = 24 sin 105 = 23.1822$

Area of triangle

= $1/2 (23.1822)(12)\\= 142.932$

6 0

4 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago