Option C is the correct values of the relationship between the number of cakes the baker makes and the number of bags of flour uses.
Solution:
Option A: Ratio of cakes baked to bags of flour used
![$\frac{9}{4}, \frac{18}{6}=\frac{3}{1} \text { and } \frac{27}{9}=\frac{3}{1}](https://tex.z-dn.net/?f=%24%5Cfrac%7B9%7D%7B4%7D%2C%20%5Cfrac%7B18%7D%7B6%7D%3D%5Cfrac%7B3%7D%7B1%7D%20%5Ctext%20%7B%20and%20%7D%20%5Cfrac%7B27%7D%7B9%7D%3D%5Cfrac%7B3%7D%7B1%7D)
Here the ratios are not same.
So, this option is not true.
Option B: Ratio of cakes baked to bags of flour used
![$\frac{6}{2}=\frac{3}{1}, \frac{12}{4}=\frac{3}{1} \text { and } \frac{18}{6}=\frac{3}{1}](https://tex.z-dn.net/?f=%24%5Cfrac%7B6%7D%7B2%7D%3D%5Cfrac%7B3%7D%7B1%7D%2C%20%5Cfrac%7B12%7D%7B4%7D%3D%5Cfrac%7B3%7D%7B1%7D%20%5Ctext%20%7B%20and%20%7D%20%5Cfrac%7B18%7D%7B6%7D%3D%5Cfrac%7B3%7D%7B1%7D)
Here the ratios are same.
So, this option is true.
Option C: Ratio of cakes baked to bags of flour used
![$\frac{4}{9}, \frac{6}{18}=\frac{1}{3} \text { and } \frac{9}{17}](https://tex.z-dn.net/?f=%24%5Cfrac%7B4%7D%7B9%7D%2C%20%5Cfrac%7B6%7D%7B18%7D%3D%5Cfrac%7B1%7D%7B3%7D%20%5Ctext%20%7B%20and%20%7D%20%5Cfrac%7B9%7D%7B17%7D)
Here the ratios are not same.
So, this option is not true.
Option D: In this table cakes baked is 6 and the bags of flour is 18.
But a baker made 18 cakes using 6 bags of flour.
So, this option is not true.
Hence option C is the correct values of relationship between the number of cakes the baker makes and the number of bags of flour uses.
Lateral surface area is given as the area of all sides of a figure excluding the area of the base where as surface area is the sum of the areas of all faces of the solid.
Step-by-step explanation:
Lateral surface area is given as the area of all sides of a figure excluding the area of the base where as surface area is the sum of the areas of all faces of the solid.
If given total surface area, you can find lateral surface area by subtracting the area of the base from the surface area of the solid.
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Surface area and lateral surface area:brainly.com/question/14028871
Keywords : difference, lateral,surface area,total surface area
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Answer:
38% probability that a randomly selected student is female or a physics major.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Desired outcomes:
Physics majors or female
10 physics majors(of which 3 are female).
12 female(the 3 female physics majors have already been counted, so we count 9)
![D = 10 + 9 = 19](https://tex.z-dn.net/?f=D%20%3D%2010%20%2B%209%20%3D%2019)
Total outcomes:
50 students, so ![T = 50](https://tex.z-dn.net/?f=T%20%3D%2050)
Probability
![p = \frac{D}{T} = \frac{19}{50} = 0.38](https://tex.z-dn.net/?f=p%20%3D%20%5Cfrac%7BD%7D%7BT%7D%20%3D%20%5Cfrac%7B19%7D%7B50%7D%20%3D%200.38)
38% probability that a randomly selected student is female or a physics major.
If two line segments intersect at 90 degrees, then two line segments are perpendicular.
Answer:
1 point. O (0,0)
Step-by-step explanation:
Hi
Invariant points are those points who remain on the same location after a given transformation.
1. Plotting OABC we have it below:
2. Whenever we dilate centered, the image O'A'B'C' will be determined by the following points:
![O'(0,0) \:A'(3,0) B'(6,6) \:and\:C'(0,6)](https://tex.z-dn.net/?f=O%27%280%2C0%29%20%5C%3AA%27%283%2C0%29%20B%27%286%2C6%29%20%5C%3Aand%5C%3AC%27%280%2C6%29)
Since the Scale factor is (2)
3. Check it out O'A'B'C' below
4. On the perimeter of O'A'B'C' (enlarged OABC) we have left 1 point invariant.