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3 years ago

Can I I please get some help?

Mathematics

1 answer:

o-na [289]3 years ago

8 0

24 square units
because 8*3=24 square units

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The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

lorasvet [3.4K]

<span>The domain of the function can be obtained by pluging the values of the range into f(x), i.e domain = {k^2 + 2k + 1 = 25, k^2 + 2k + 1 = 64} = {k^2 + 2k - 24 = 0, k^2 + 2k - 63 = 0}. Solving the two quadratic equations, we have that the range is {-9, -6, 4, 7}.I hope that my answer is helpful! Let me know if you need something more :)</span>

3 0

3 years ago

A rocket is 1 mile above the earth in 30 seconds and 5 miles above the earth in 2.5 minutes. What is the rockets rate of change

Aleksandr-060686 [28]

<span>The constant rate of change is 30 seconds because:
1 mile=30 seconds
2 miles=1 minute
3 miles=1 minute and 30 seconds
4 miles=2 minutes
5 miles=2 minutes and 30 seconds
or in other words 2.5</span>

6 0

3 years ago

Solve for x! Please help!

erica [24]

Answer:

Step-by-step explanation:

ΔADC and ΔCDB are similar (AA). Therefore the sides are in proportion:

$\dfrac{AD}{DC}=\dfrac{DC}{DB}$

We have AD = 16, DC = x, DB = 9. Substitute:

$\dfrac{16}{x}=\dfrac{x}{9}$ <em>cross multiply</em>

$x^2=(16)(9)\to x=\sqrt{(16)(9)}\\\\x=\sqrt{16}\cdot\sqrt9\\\\x=4\cdot3\\\\x=12$

3 0

3 years ago

ken wants to rent a car for a week and to pay to more than $130. how far can he drive if the car rental cost $94 a week plus $0.

cupoosta [38]

If Ken wants to pay more than 130, he needs to drive more than 90 miles. You subtract 94 from 130, which equals 36. 36 divided by .4 (for the price per mile) and it equals 90.

4 0

4 years ago

You are sitting on the ground flying a kite.

Neko [114]

Answer:

Height of the kite = 36 feet

Step-by-step explanation:

Triangle attached in the figure shows the complete picture,

I am sitting at point A, string connecting the kite and me is side AC, height of the kite from the ground is side BC and side AB representing the distance between me and the kite.

Length of side BC = h

Length of side AC = 39 feet

Length of side AB = 15 feet

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

(39)² = (15)² + h²

h² = 1521 - 225

h² = 1296

h = √1296

h = 36 feet

Therefore, kite is at 36 feet height.

5 0

3 years ago