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dem82 [27]
3 years ago
7

If an angle is three times of its supplement, find the angle​

Mathematics
1 answer:
zavuch27 [327]3 years ago
5 0

Answer:

<h2>135° angle</h2>

Let the angle be x it's supplement = (180-x)

x = 3 (180-x)

⇒x=540−3x

⇒4x=540⇒x=135°

Step-by-step explanation:

Hope it is helpful....

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Pls can someone answer how to round 5pi to the nearest 10th I’ll give you brain points or whatever
mojhsa [17]

Answer:

Step-by-step explanation:

5\pi=15.70...

To round a number to the nearest tenth , look at the next place value to the right (the hundredths)which is 0 in this question.

Thus, it will become 15.7

4 0
3 years ago
During the past 10 years, the amount of money, M (in billions of dollars), spent in North America by car dealerships advertising
rewona [7]

Answer: I believe the 23rd, but if its in 10 years I must be wrong

I graphed the equation, but replaced t with x




6 0
3 years ago
What is the prime factorization of the number 55?
Simora [160]

Answer:

11 if im right :)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Mathematics with applications in the management, Natural, and Social Sciences Twelfth edition
Fiesta28 [93]

Answer: 2014

Step-by-step explanation:

LED: -25x + 6y = 20

CFL: 15x + 2y = 322

we need to find which year it was the same to know where LED lighting surpassed  CFL lighting

-25x + 6y = 20

15x + 2y = 322 (-3)

-25x + 6y = 20

<u>-45x - 6y = -966     </u>

-70x = -946

x = 13.51

The nearest year would be 14 which is 2014

8 0
3 years ago
Use synthetic division and remainder theorem p(x) = 3x^3 - 5x^2 - x + 2. p(-1/3)=
Alik [6]

Answer:

5/3

Step-by-step explanation:

-1/3 goes on the outside and since we have our polynomial in standard form with no in between terms missing, 3,-5,-1,2 go inside because they are the coefficients of our polynomial.

-1/3   |   3      -5          -1          2

       |

         -------------------------------------

First step bring the 3 down inside. (3+0=3)

-1/3   |   3      -5          -1          2

       |

         -------------------------------------

           3

Whatever goes below the bar, must be multiplied by outside number and put directly below next number inside.

-1/3   |   3      -5          -1          2

       |             -1

         -------------------------------------

           3

The numbers lined up vertically are added to get the numbers underneath the bar.

-1/3   |   3      -5          -1          2

       |             -1

         -------------------------------------

           3        -6

Again any number below the bar gets multiply to the number outside.

-1/3   |   3      -5          -1          2

       |             -1          2

         -------------------------------------

           3        -6

Again the numbers lined up vertically above the bar get added to get the number that goes underneath the bar there.

-1/3   |   3      -5          -1          2

       |             -1          2

         -------------------------------------

           3        -6          1

Multiply to outside number 1(-1/3)=-1/3.

This goes under the 2 inside.

-1/3   |   3      -5          -1          2

       |             -1          2          -1/3

         -------------------------------------

           3        -6          1

The last number we are fixing to be put is the remainder of (3x^3-5x^2-x+2)/(x+1/3) or you could say it is the value of p(-1/3) since:

P(x)/(x-c)=Q(x)+R/(x-c)

Multiply both sides by (x-c):

P(x)=Q(x)(x-c)+R

If you evaluate P at x=c, we get R:

P(c)=Q(c)(c-c)+R

P(c)=Q(c)*0+R

P(c)=R.

Let's finish:

-1/3   |   3      -5          -1          2

       |             -1          2          -1/3

         -------------------------------------

           3        -6          1         5/3

This means p(-1/3)=5/3.

We could have also got this by directly plugging in (-1/3) for x into 3x^3-5x^2-x+2.

7 0
3 years ago
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