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3 years ago

A Me and Ed's Pizza has 16 slices. John eat 7/12pieces of pizza. Harold

Physics

1 answer:

aksik [14]3 years ago

5 0

Answer:

Explanation:

Total number of slices in the pizza = 16

Total number ate by John,

J = 7/12 * 16 = 28/3 = 9.3

Total number ate by Harold,

H = 4/23 * 16 = 2.783

Total number left over

L = 1/23 * 16 = 0.696

Total number ate by Betty

B = ?

All we have to do to get the total number eaten by Betty is to sum up that eaten by Harold and John, including the left over, then subtract it from the total pizza slices.

Betty = Total - (Harold + John + Left Over)

Betty = 16 - (9.3 + 2.783 + 0.696)

Betty = 16 - 12.779

Betty = 3.221

Therefore, Betty ate 3.221 of the total pizza as a whole

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Explanation:

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3 years ago

What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use

marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

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Force $F_{2}=26\ N$

Force $F_{3}=14\ N$

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Using formula of torque

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$\tau_{1}=-F_{1}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{1}=-18\times\dfrac{0.2}{2}$

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We need to calculate the torque due to force F₂

Using formula of torque

$\tau_{2}=F_{2}d_{2}$

$\tau_{2}=F_{2}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{2}=26\times\dfrac{0.2}{2}$

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We need to calculate the torque due to force F₃

Using formula of torque

$\tau_{3}=F_{3}d_{3}$

$\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{3}=0.1(14\sin45+14\cos45)$

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$\tau=\tau_{1}+\tau_{2}+\tau_{3}$

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$\tau=2.72\ N-m$

Hence, The net torque on the square plate is 2.72 N-m.

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3 years ago

An 8.2 kg object accelerates at 8.0 m/s^2. What is the acceleration?

Elina [12.6K]

Answer:

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We know that F = ma,

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2 years ago

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