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Nadusha1986 [10]
4 years ago
15

What is a substance?

Physics
1 answer:
ycow [4]4 years ago
3 0

A.a uniform mixture that can’t be separated

"substance" seems vague here

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A jet airliner moving initially at 406 mph (with respect to the ground) to the east moves into a region where the wind is blowin
astraxan [27]

Answer:

966 mph

Explanation:

Using as convention:

- East --> positive x-direction

- North --> Positive y-direction

The x- and y- components of the initial velocity of the jet can be written as

v_{1x} = 406 mph\\v_{1y} = 0

While the components of the velocity of the wind are

v_{2x} = (568)(cos 15^{\circ})=548.6 mph\\v_{2y} = (568)(sin 15^{\circ})=147.0 mph

So the components of the resultant velocity of the jet are

v_x = v_{1x}+v_{2x}=406+548.6=954.6 mph\\v_y = v_{1y}+v_{2y}=0+147.0=147.0 mph

And the new speed is the magnitude of the resultant velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(954.6)^2+(147.0)^2}=965.8 mph \sim 966 mph

6 0
3 years ago
Which instrument is launched into the atmosphere to collect pressure, temperature, humidity, wind speed, and other data?
koban [17]
C. Radiosonde is the answer

the above mentioned is not correct
5 0
3 years ago
Which of the following is true about producers?
Nina [5.8K]

the answer is d they are essential to all ecosystems
4 0
3 years ago
How many oxygen atoms are in Ca (NO3)2
Lapatulllka [165]

There are 6 atoms of oxygen in Ca (NO3)2.

5 0
3 years ago
Hi there, it is your average pathetic Junior. Anyways, I need help on 8&9 ASAP, this assignment is beyond overdue but hey wh
zheka24 [161]

Answer:

a) -31.36 m/s

b) 50.176 m

Explanation:

<h2>a) Velocity of the bag</h2>

This is a problem of motion in one direction (specifically vertical motion), and the equation that best fulfills this approach is:

V_{f}=V_{o} +a.t  (1)

Where:

V_{f} is the final velocity of the supply bag

V_{o}=0 is the initial velocity of the supply bag (we know it is zero because we are told <u>it was "dropped", this means it goes to ground in free fall</u>)

a=g=-9.8m/s^{2} is the acceleration due gravity (the negtive sign indicates the gravity is downwards, in the direction of the center of the Earth)

t=3.2s is the time

Knowing this, let's solve (1):

V_{f}=0+(-9.8m/s^{2})(3.2s)  (2)

Hence:

V_{f}=-31.36m/s  Note the negative sign is because the direction of the bag is downwards as well.

<h2>b) Final height of the bag</h2>

In this case we will use the following equation:

y=V_{o}t-\frac{1}{2}gt^{2} (3)

Where:

y is the distance the bag has fallen

V_{o}=0 remembering <u>the bag was dropped</u>

g=-9.8m/s^{2} is the acceleration due gravity (downwards)

t=3.2 s is the time

Then:

y=-\frac{1}{2}gt^{2} (3)

y=-\frac{1}{2}(-9.8m/s^{2})(3.2)^{2} (4)

Finally:

y=50.176 m

4 0
3 years ago
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