Solution :
Given :
The angle of the first maximum with the center is given by :
![$a=\tan^{-1}\left(\frac{0.488}{1.88}\right)$](https://tex.z-dn.net/?f=%24a%3D%5Ctan%5E%7B-1%7D%5Cleft%28%5Cfrac%7B0.488%7D%7B1.88%7D%5Cright%29%24)
= 14.5°
The grating distance can be calculated as :
![$d=\frac{1 \ cm}{5308 \text{ slits}}$](https://tex.z-dn.net/?f=%24d%3D%5Cfrac%7B1%20%5C%20cm%7D%7B5308%20%5Ctext%7B%20slits%7D%7D%24)
= ![$1.88 \times 10^{-4} \ m$](https://tex.z-dn.net/?f=%241.88%20%5Ctimes%2010%5E%7B-4%7D%20%5C%20m%24)
When the principal maxima yields at y = 0.488 m and the length from the wall 1.88 m. Thus the equation of the wavelength is :
, where n = 1
![$=1.88 \times 10^{-4} \times \sin (14.5)$](https://tex.z-dn.net/?f=%24%3D1.88%20%5Ctimes%2010%5E%7B-4%7D%20%5Ctimes%20%5Csin%20%2814.5%29%24)
![$=4.70 \times 10^{-5} \ m$](https://tex.z-dn.net/?f=%24%3D4.70%20%5Ctimes%2010%5E%7B-5%7D%20%5C%20m%24)
Your answer will be (B) - intense pressure.
Answer:CANT SEE THE PICTURE
ch
Explanation:
NEED A BETTER PHOTO