Answer:
1.a=2
2. C x=2 and x=-3
Step-by-step explanation:
The standard form for the quadratic function is
ax^2 +bx+c
so we need to rewrite the function to be in this form
2x^2 -10 = 7x
Subtract 7x from each side
2x^2 -7x-10 = 7x-7x
2x^2 -7x-10 = 0
a =2, b= -7 c=-10
2. The quadratic formula is
-b ± sqrt(b^2 -4ac)
----------------------------
2a
2x^2 + 2x=12
Lest get the equation in proper form
2x^2 + 2x-12 = 12-12
2x^2 +2x-12 =0
a=2 b=2 c=-12
Lets substitute what we know
-2 ± sqrt(2^2 -4(2)(-12))
----------------------------
2(2)
-2 ± sqrt(4+96)
----------------------------
2(2)
-2 ± sqrt(100)
----------------------------
4
-2 ± 10
----------------------------
4
-2 + 10 -2-10
----------- and --------------
4 4
8/4 and -12/4
2 and -3
Answer:
Step-by-step explanation:
The difference of the rational and and irrational number is always an irrational number.
Correct choice is B
Answer:
A. x
C. x – 5
D. x + 2
Step-by-step explanation:
From the question above, we are asked to find the factors of an algebraic expression that is given as:
x³ - 3x² - 10x
We would use the step of factorisation
Step 1
x(x² - 3x- 10)
The first factor of the algebraic expression has been obtained = x
Step 2
We factorise x² - 3x - 10
x² +2x - 5x - 10
(x²+2x) - (5x - 10)
x(x + 2) -5(x + 2)
(x + 2)(x - 5)
Step 3
x³ - 3x² - 10x
x(x² - 3x- 10)
(x)(x + 2)(x - 5)
Therefore, the factors of the algebraic expression are:
(x), (x + 2), (x - 5)
