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Over [174]
3 years ago
6

A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is labeled as x degrees

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0

The Question is incomplete the Complete Question is

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is labeled as x degrees. The side adjacent to the acute angle has length 6 centimeters and the side opposite to the acute angle has length 8 centimeters. What is the value of tan x°?

Answer:

Therefore the value of tan x is

\tan x=\dfrac{4}{3}

Step-by-step explanation:

Given:

hypotenuse = 10 cm'

side adjacent to the acute angle 'x' = 6 cm.

side opposite to the acute angle 'x' = 8 cm.

To Find:

tan x = ?

Solution:

In Right Angle Triangle , Tan Identity we have

\tan x= \dfrac{\textrm{side opposite to angle x}}{\textrm{side adjacent to angle x}}

Substituting the values we get

\tan x= \dfrac{8}{6}=\dfrac{4}{3}

Therefore the value of tan x is

\tan x=\dfrac{4}{3}

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3 years ago
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Answer:

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Step-by-step explanation:

Perhaps you want the solution to ...

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3 years ago
4n+3< 6n+8 -2n what is n
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Answer:

<em />8>3<em />

Step-by-step explanation:

STEP 1: <em>Rewrite so   n is on the left side of the inequality.</em>

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STEP 2: <em>Subtract  2 n  from  6 n .</em>

4n+8>4n+3

STEP 3: <em>Move all terms containing  n  to the left side of the inequality.</em>

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Answer:

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given  

                cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

                  cos( 3x - \frac{\pi }{3} )  = cos (\frac{\pi }{6} )

                      3x - \frac{\pi }{3}  =  \frac{\pi }{6}

                      3x - \frac{\pi }{3  } + \frac{\pi }{3}   =  \frac{\pi }{6} + \frac{\pi }{3}

                      3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}

                     x = \frac{\pi }{6}

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

<u><em>verification </em></u>:-

      cos( 3x - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

put  x = \frac{\pi }{6}

    cos( 3(\frac{\pi }{6})  - \frac{\pi }{3} )  = \frac{\sqrt{3} }{2}

    cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} =  \frac{\sqrt{3} }{2}

Both are equal

∴The solution of the given trigonometric equation

                   x = \frac{\pi }{6}

                     

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