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Over [174]
3 years ago
6

A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is labeled as x degrees

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0

The Question is incomplete the Complete Question is

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is labeled as x degrees. The side adjacent to the acute angle has length 6 centimeters and the side opposite to the acute angle has length 8 centimeters. What is the value of tan x°?

Answer:

Therefore the value of tan x is

\tan x=\dfrac{4}{3}

Step-by-step explanation:

Given:

hypotenuse = 10 cm'

side adjacent to the acute angle 'x' = 6 cm.

side opposite to the acute angle 'x' = 8 cm.

To Find:

tan x = ?

Solution:

In Right Angle Triangle , Tan Identity we have

\tan x= \dfrac{\textrm{side opposite to angle x}}{\textrm{side adjacent to angle x}}

Substituting the values we get

\tan x= \dfrac{8}{6}=\dfrac{4}{3}

Therefore the value of tan x is

\tan x=\dfrac{4}{3}

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boyakko [2]

Answer: The answer is 43.5 because when using the formula you get this result.

Step-by-step explanation: Area of triangle is base x height divided by 2. So do our base 14.5 and our height 6 and multiply them together. 14.5 x 6 = 87 / 2 = 43.5

6 0
3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

3 0
3 years ago
Which word best describes the degree of overlap between the two data sets?
snow_tiger [21]

Answer:

Moderate

Step-by-step explanation:

I think sorry if its wrong

6 0
3 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
2 years ago
A chef draws cookies randomly from a box containing 6 cookies of the same shape and size. There is 1 chocolate cookie, 3 almond
vovangra [49]

Answer:

1/5

Step-by-step explanation:

The probability of drawing an almond cookie the first time is 3/6=1/2, since there are a total of 6 cookies and 3 of them are almond. However, the second time the chance is 2/5, since there are 5 cookies left and only two of them are almond. The equation to model this is therefore:

P=\dfrac{1}{2}\cdot \dfrac{2}{5}=\dfrac{1}{5}

Hope this helps!

8 0
3 years ago
Read 2 more answers
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