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emmainna [20.7K]
3 years ago
13

Convert 60mph to feet per minute

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0
Ummmmmmmmmmmmmmmmmmmmmm
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In 5 minutes, Joey eats 25 hot dogs. how many hot dogs did he eat in a minute?​
Colt1911 [192]
Answer: He Had 5 Per Min.

25 ÷ 5 = 5

5 Per Min.
4 0
3 years ago
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In the function f(x)=(x-2)^2+4, the minimum value occurs when x is
Vinil7 [7]

The graph of the function is a parabola. 

The nose comes down as far as y=4 but no farther.

That happens when  (x - 2)² = 0 , and THAT happens when x = 2 .

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3 years ago
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Find the sum of 8 + 11 + 14 + ... + 602 + 605.
Sedbober [7]

Answer:

1,240

Step-by-step explanation:

Okay so, 8+11=19 then 19+14= 33. 33+602= 635 Finally, 635+605 should = 1,240.

8 0
3 years ago
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??????????????????????
ale4655 [162]

Answer:

Area = 58 \ units^2

Step-by-step explanation:

We can start by finding the third side of the triangle/the side of the square using the Pythagorean Theorem:

a^2+b^2=c^2

In this case the side length of the square would be represented by the variable "c" as it is the hypotenuse:

3^2+7^2=c^2

9+49=c^2

c^2=58

c=\sqrt{58}

Since the area of a square is the side length square then...

Area =( \sqrt{58} )^2

The square root and the squared cancel out giving us...

Area = 58 \ units^2

3 0
3 years ago
What is the difference between bernoulii equation and riccati equation
melisa1 [442]
The Bernoulli equation is almost identical to the standard linear ODE.

y'=P(x)y+Q(x)y^n

Compare to the basic linear ODE,

y'=P(x)y+Q(x)

Meanwhile, the Riccati equation takes the form

y'=P(x)+Q(x)y+R(x)y^2

which in special cases is of Bernoulli type if P(x)=0, and linear if R(x)=0. But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as P,Q,R for brevity.

For Bernoulli equations, the standard approach is to write

y'=Py+Qy^n
y^{-n}y'=Py^{1-n}+Q

and substitute v=y^{1-n}. This makes v'=(1-n)y^{-n}y', so the ODE is rewritten as

\dfrac1{1-n}v'=Pv+Q

and the equation is now linear in v.

The Riccati equation, on the other hand, requires a different substitution. Set v=Ry, so that v'=R'y+Ry'=R'\dfrac vR+Ry'. Then you have

y'=P+Qy+Ry^2
\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}
v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2

Next, setting v=\dfrac{u'}u, so that v'=\dfrac{uu''-(u')^2}{u^2}, allows you to write this as a linear second-order equation. You have

\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}
u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0
u''+Su'+Tu=0

where S=-\left(Q+\dfrac{R'}R\right) and T=PR.
3 0
3 years ago
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