Answer:
Given two items with a price and quantity, this determines which is the better buy by comparing unit prices. Finds the better deal.
Binomial Distribution
Calculates the probability of 3 separate events that follow a binomial distribution. It calculates the probability of exactly k successes, no more than k successes, and greater than k successes as well as the mean, variance, standard deviation, skewness and kurtosis.
Also calculates the normal approximation to the binomial distribution with and without the continuity correction factor
Calculates moment number t using the moment generating function
Binomial Option Pricing Model
This shows all 2t scenarios for a stock option price on a binomial tree using (u) as an uptick percentage and (d) as a downtick percentage
Bond Flat Price-Accrued Coupon-Market Price
Calculates the flat price, accrued coupon, and market price for a bond between valuation dates using the following methods:
1) Theoretical Method
2) Practical Method
3) Semi-Theoretical Method
Step-by-step explanation:
5......................................
The expression that is not equivalent to (1 - sin²(x)) tan(-x) is D. (cos²x - 1)(cot -x).
<h3>How to illustrate the expression?</h3>
It should be noted that (cos²x - 1)(cot -x). is not equivalent to the given expression.
This is illustrated as:
(cos²x - 1)(cot -x)
= (-sin²x) × (-cot x)
= sin²x × cosx/sin x = sinxcosx
In conclusion, the correct option is D.
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The expression _______ is not equivalent to (1 − sin2(x)) tan(-x).
a. (1 - cos^2(x)) cot(-x)
b. (cos^2(x) - 1) cot(x)
c. (sin^(x) - 1) tan(x)
d. (cos^2(x) - 1) cot(-x)
Answer:
12 :)
Step-by-step explanation:
np
Answer: 20160
Step-by-step explanation:
Here, the total number of character = 8 ( 1, 2, 3, 4, 5, X, Y, Z)
Since, we have to form a code by any 6 character from these character.
If there are no repeated character in any code.
Then, In the code,
The total possible outcomes of first digit = 8
The total possible outcomes of second digit = 7
The total possible outcomes of third digit = 6
The total possible outcomes of fourth digit = 5
The total possible outcomes of fifth digit = 4
The total possible outcomes of sixth digit = 3
Therefore, the total possible codes = 8 × 7 × 6 × 5 × 4 × 3 = 20160