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Mazyrski [523]
3 years ago
11

Which table of ordered pairs represents a proportional relationship?

Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

The first table

Step-by-step explanation:

Because both side -1 every time.

Sindrei [870]3 years ago
5 0

Answer: C

Step-by-step explanation:

It represents a proportional relationship because each time they add two

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3x - 5y = 15<br> x - 4y = 12<br> Substitution method
Scorpion4ik [409]

Answer:

x=0,y=-3

Step-by-step explanation:

3x-5y=15 - equation(1)

x-4y=12 => x=12+4y -equation (2)

Replace equation (2) in equation (1)

3(12+4y)-5y=15

36+12y-5y=15

7y=15-36

7y= -21

y = -21/7

y=-3

If y=-3,then replace in equation (1) ; 3x -5(-3)=15

3x+15=15

3x=0

x=0

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You can find the volume of a box by
Hatshy [7]

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A

Step-by-step explanation:

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What is the pair of angles called.
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3 years ago
At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen
guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

p_1 = \frac{20}{100} = 0.2

s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04

p2 -> 1997

10 out of 100, so:

p_2 = \frac{10}{100} = 0.1

s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03

Distribution of p1 – p2:

p = p_1 - p_2 = 0.2 - 0.1 = 0.1

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05

Confidence interval:

p \pm zs

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.  

The lower bound of the interval is:

p - zs = 0.1 - 1.645*0.05 = 0.01775&#10;

The upper bound of the interval is:

p + zs = 0.1 + 1.645*0.05 = 0.18225&#10;

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

6 0
3 years ago
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