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Mazyrski [523]
3 years ago
11

Which table of ordered pairs represents a proportional relationship?

Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

The first table

Step-by-step explanation:

Because both side -1 every time.

Sindrei [870]3 years ago
5 0

Answer: C

Step-by-step explanation:

It represents a proportional relationship because each time they add two

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ABC is an isosceles<br> AB= 3x-4 and BC= 5x-10<br><br> what is AB?
kakasveta [241]
3x-4=5x-10
Subtract 3x from both sides
-4=2x-10
Add 10 to both sides
6= 2x
X= 3
3 times 3-4
AB=5
3 0
2 years ago
Read 2 more answers
The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec
elena-14-01-66 [18.8K]

If S(t) is the amount of strontium-90 present in the area in year t, and it decays at a rate of 2.5% per year, then

S(t+1)=(1-0.025)S(t)=0.975S(t)

Let S(0)=s be the starting amount immediately after the nuclear reactor explodes. Then

S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)

or simply

S(t)=0.975^ts

So that after 50 years, the amount of strontium-90 that remains is approximately

S(50)=0.975^{50}s\approx0.282s

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

S(t)=se^{kt}

where t is measured in years. We're told that 2.5% of the starting amount s decays after 1 year, so that

0.975s=se^k\implies k=\ln0.975

Then after 50 years, we have

S(50)=se^{50k}\approx0.282s

5 0
3 years ago
Anyone help please!!!!
Andre45 [30]
We are to verify the identity:

cos(α-B)-cos(α+B) = 2 sinα sinβ

Left hand side = cos(α - B)-cos(α + B) 

= cosα cosβ + sinα sinB - (cosα cosB - sinα sinβ)

= cosα cosβ + sinα sinB - cosα cosB + sinα sinβ)

= sinα sinβ + sinα sinβ

= 2 sinα sinβ

= Right Hand side
6 0
3 years ago
Read 2 more answers
Turn this improper fraction in mixed numbers.23/7​
Pavel [41]

Answer:

3  2 /7

Step-by-step explanation:

Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

3 0
2 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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