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3 years ago

Find the coordinates of the points of intersection of the graphs with coordinate axes:

Mathematics

1 answer:

ioda3 years ago

5 0

Answer:

x - intercept = (4,0)

y - intercept = (0,-6)

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200 + 10x = 120 + 15x now solve the equation to find x, the number of hours that both companies will charge the same ammount

torisob [31]

Answer:

Step-by-step explanation:

Given the equation, $200 + 10x = 120 + 15x$ , let's solve for x as follows,

Subtract 200 from both sides

$200 + 10x - 200 = 120 + 15x - 200$

$10x = - 80 + 15x$

Subtract 15x from both sides

$10x - 15x = - 80 + 15x - 15x$

$-5x = - 80$

Divide both sides by -5

$\frac{-5x}{-5} = \frac{-80}{5}$

$x = 16$

8 0

3 years ago

What is the answer to this problem

Aleks04 [339]

Answer:

14 cm^2

Step-by-step explanation:

You find the area of both triangles, and subtract by 4

6x3x1/2x2 - 2x2

18 - 4

3 0

3 years ago

Caleb strung a 12 foot rope from the bottom of one fence post to the top of another. He measured the angle of elevation of the r

OLEGan [10]

The answer for this question is b because the angle of elevation of the rope as 35°

5 0

3 years ago

What is the slope of the line that passes through the points (4, 9) and (1, 6)?

Aleksandr [31]

a = ( 1 , 6 )

b = ( 4 , 9 )

$slope = \frac{y(b) - y(a)}{x(b) - x(a)} \\$

Now just need to put the coordinates in the above equation :

$slope = \frac{9 - 6}{4 - 1} \\$

$slope = \frac{3}{3} \\$

$slope = 1$

And we're done...♥️♥️♥️♥️♥️

5 0

3 years ago

A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.

madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X ≥ 65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean ( $\mu_x$ ) = 64 and a standard deviation ( $\sigma_x$ ) = $\frac{19}{\sqrt{14} }$

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

$z=\frac{x-\mu_x}{\sigma_x}$ but μ=64 and σ=19 and n=14, $\mu_x=\mu=64$ and $\sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }$

Therefore: $z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83$

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X ≥ 65.6)

First me need to calculate the z score (z). This is given by the equation:

$z=\frac{x-\mu_x}{\sigma_x}$

Therefore: $z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32$

From z table, P(X ≥ 65.6) = P(z ≥ 0.32) = 1 - P(z < 0.32) = 1 - 0.6255 = 0.3745

P(X ≥ 65.6) = 0.3745

P(X < 68.2) = 0.7967

5 0

3 years ago