Yes!
- you applied the distributive property
- combined like terms
- and answered the rest right!
Thats insane tho!
Whats ur aops class that you take?
I think it’s 15 sorry if I’m wrong
<h3><u>
Answer:</u></h3>
- The chance of getting a 5 or 6 in the next turn is about 40%.
<h3><u>Step-by-step explanation:</u></h3>
- => (5 + 3) ÷ (3 + 3 + 0 + 6 + 3 + 5)
- => 8 ÷ 20
- => 8/20
- => 4/10
- => 0.40
- => 0.40 x 100
- => 40%
<h3><u>Conclusion:</u></h3>
Therefore, the chance of getting a 5 or 6 in the next turn is about 40%.
Hoped this helped

Answer: Part A : c = n.p
Part B = 366 moviegoers
Step-by-step explanation: In part A, to predict the number of moviegoers, we have to find the <u>proportion</u> of the sample that does the activity, which will called <u>p</u>. Since <u>p</u> is a percentage, to determine how many moviegoers are seeing a comedy, you multiply it by the sample size, <u>n</u>.
Therefore: c = n.p
For part B, based on the the sample:
p =
= 0.24
The total population is given: 1,525
c = 0.24.1,525
c = 366
Based on the sample, <u>366</u> <u>people</u> are seeing a comedy.