Answer:
The given coordinates of the points A and C of the right triangle ABC are (2, 5) and (-2, 3) respectively
The possible pairs of the coordinates of the point B are found as follows;
1) Draw a horizontal line from the point C to the right and a vertical line down from the point A to get the point B at (2, 3) which is the point of the perpendicular intersection of the two constructed lines above
2) Draw a vertical line from the point C upwards and a horizontal line to the left from the point A to get the point B at (-2, 5) which is the point of the perpendicular intersection of the two newly constructed lines here
Step-by-step explanation:
3(5+7) is the problem you are looking at. To figure it out, you can use properties. On the right side of the equals sign, it shows a property you can use to do the problem. In this case, they are distributing.
The answer are (1, 5) and (1, 3)
To make a fraction to its simplest form, you have to divide the numerator and the denominator by the same number. For this question, divide 140 and 216 by 4. You will get 35/54. Since you can't divide this further, the simplest form of 140/216 is 35/54.
<em>Hope it helps</em> :)