2 years ago

20 POINTS, and BRAINIEST

Mathematics

2 answers:

Licemer1 [7]2 years ago

6 0

Answer:

51.20

Step-by-step explanation:

mel-nik [20]2 years ago

4 0

Answer:

the answer is ..........

$51.20

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Prove that 1/sin^2A -1/tan^2A= 1

Vika [28.1K]

Answer:

Step-by-step explanation:

$LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS$

Hint: 1 - Cos² A = Sin² A

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Answer:

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Step-by-step explanation:

1/2 = 2/4

____________________________________________________________

1/4x + 3/4 = 2/4

-3/4 -3/4

1/4x = -1/4

divide by -1/4

x = -1

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77julia77 [94]

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