The probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute is 0.4582.
Given that the population mean, 
= 90 wpm
The standard deviation of the population ,
= 10
Sample size, n = 12
Sample mean, 
= 95
The reading rate of students follows the normal distribution.
Let z = 
= 
= 1.732
Probability that the mean reading exceeds 95 wpm = P( >95)
= P(z>1.732)
= 1- P(z<1.732)
= 0.4582
[The value 0.4582 found from the area under the normal curve using tables].
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Answer:
The confidence interval for the mean weight of high school girls in kilograms would have been would have been (46.5, 48.41).
Step-by-step explanation:
To find the interval, we can just make the conversion of the values from pounds to kilograms.
Each kilogram has 2.2 pounds. So, to realize the conversion from pounds to kilograms, we divide by 2.2.
Confidence interval: (102.3 pounds, 106.5 pounds).
102.3 pounds = 102.3/2.2 = 46.5 kilograms
106.5 pounds = 106.5/2.2 = 48.41 kilograms
The confidence interval for the mean weight of high school girls in kilograms would have been would have been (46.5, 48.41).
Answer:
(x-3) is the correct expression
Step-by-step explanation:
To factor you split the expression apart -
x² + 2x – 15
This breaks up to (x+5)(x-3)
If you multiply (FOIL) these you get your expression x² + 2x – 15
Your answer choices do not include (x+5) so it must be (x-3)
<em>I hope this helps!</em>
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Answer:
f'(t) = 4t + 3
Step-by-step explanation:
f(t) = 2t^2 + 3t - 6
f'(t) = 4t + 3 - 0
f'(t) = 4t + 3
