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Naily [24]
3 years ago
11

Suppose a 99% confidence interval for the mean weight of high school girls in pounds is (102.3, 106.5). If we had measured the w

eights of each of the girls in kilograms (2.2 pounds = 1 kilogram) then the confidence interval for the mean weight of high school girls in kilograms would have been
Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

Answer:

The confidence interval for the mean weight of high school girls in kilograms would have been would have been (46.5, 48.41).

Step-by-step explanation:

To find the interval, we can just make the conversion of the values from pounds to kilograms.

Each kilogram has 2.2 pounds. So, to realize the conversion from pounds to kilograms, we divide by 2.2.

Confidence interval: (102.3 pounds, 106.5 pounds).

102.3 pounds = 102.3/2.2 = 46.5 kilograms

106.5 pounds = 106.5/2.2 = 48.41 kilograms

The confidence interval for the mean weight of high school girls in kilograms would have been would have been (46.5, 48.41).

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The citizens of a certain community were asked to choose their favorite pet. The pie chart below shows the distribution of the c
Arturiano [62]

Incomplete Question:

The content of the pie chart is as follows:

<em>Hamsters  = 9% ; Snakes  = 10% ; Cats  = 23% </em>

<em> Birds  = 21% ;  Dogs  = 26% ;  Fish  = 11%</em>

<em></em>

Answer:

The number of citizens who chose cat or fish is 47,600

Step-by-step explanation:

Given

Number of citizens = 140,000

Required

Determine the number of those that chose fish or cats

First, we need to calculate the percentage of those whose pets are either cats or fish

Percentage = Cat + Fish

Substitute 23% for cat and 11% for fish

Percentage = 23\% + 11\%

Percentage = 34\%

Next, is to multiply the calculated percentage by the number of citizens

Cat\ or\ Fish = Percentage * Number\ of\ Citizens

Cat\ or\ Fish = 34\% * 140000

Cat\ or\ fish = 47600

<em>Hence, the number of citizens who chose cat or fish is 47,600</em>

4 0
3 years ago
Question 7 (Essay Worth 5 points)
kogti [31]

Answer:

x = -2

y=-3

(-2,-3)

Step-by-step explanation:

Both equations are equal to y

We can set them equal to each other

y = 3x + 3

y = x − 1

3x+3 = x-1

Subtract x from each side

3x+3 -x = x-1-x

2x+3 = -1

Subtract 3 from each side

2x+3-3 = -1-3

2x = -4

Divide each side by 2

2x/2 = -4/2

x = -2

Now we need to find y

y = x-1

y = -2-1

y = -3

y = x-1

3 0
3 years ago
Read 2 more answers
Brain was asked to round 4.44 to the nearest tenth and said it was 4.5 Is he correct?Why or Why not?
Annette [7]
Brian (I think you meant Brian haha..) is incorrect because the tenth place is the number right after the decimal which is a 4. If you are rounding to the tenth place that means that you have to look at the number to the right of that, which is 4. 5 and up means you round up and 4 and down means you round down. This is a 4, so you keep the 4 after the decimal and get rid of the last 4. Therefore, when rounded it would be: 4.4.
Hope this helped! Good luck! :)
5 0
3 years ago
Read 2 more answers
2x ≤ 12<br> Select the appropriate response<br> A2x ≤ 12 <br> B)x≤4 <br> C)x≤6<br> D)x ≤ 10
Monica [59]

Answer:

c x ≤ 6

Step-by-step explanation:

2x ≤ 12

Divide each side by 2

2x/2 ≤ 12/2

x ≤ 6

8 0
3 years ago
The coordinates of the endpoint of QS are Q(-9,8) and S(9,-4). Point R is on cue as such that QR:RS Is in the ratio 1:2. What ar
marishachu [46]

R(–3, 4)

Step-by-step explanation:

Let Q(-9,8) and S(9,-4) be the given points and let R(x, y) divides QS in the ratio 1:2.

By section formula,

R(x, y)=R\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=-9, y_{1}=8, \text { and } x_{2}=9, y_{2}=-4 \text { and } m=1, n=2

Substituting this in the section formula

R(x, y)=R\left(\frac{1(9)+2(-9)}{1+2}, \frac{1(-4)+2(8)}{1+2}\right)  

To simplifying the expression, we get

\Rightarrow R(x, y)=R\left(\frac{9-18}{3}, \frac{-4+16}{3}\right)

\Rightarrow R(x, y)=R\left(\frac{-9}{3}, \frac{12}{3}\right)

⇒ R(x,y) = R(–3,4)  

Hence, the coordinates of point R is (–3, 4).

6 0
3 years ago
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