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grigory [225]
3 years ago
9

Twenty dash three people purchase raffle tickets. Three winning tickets are selected at random. If first prize is ​$1000​, secon

d prize is ​$500​, and third prize is ​$100​, in how many different ways can the prizes be​ awarded?
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer: 10626

Step-by-step explanation:

Given : The total number of people purchase raffle tickets=23

The total number of prizes = 3

Since , order matters here , so we use Permutations.

The permutation of n things taken r at a time is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Then, the number of ways the prizes can be distributed :-

^{23}P_{3}=\dfrac{23!}{(23-3)!}\\\\=\dfrac{23\times22\times21\times20!}{20!}=10626

Hence, the prizes can be distributed in 10626 ways.

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I would think that all but one point would be on the line.  One way to approach this problem is to find the equation of the line based upon any two points chosen at random, and then determine whether or not the other points satisfy this equation.  Next time, would you please enclose the coordinates of each point inside parentheses:  (2.5,14), (2.25,12), and so on, to avoid confusion.
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Answer:

click on image

Step-by-step explanation:

click on the image

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