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grigory [225]
3 years ago
9

Twenty dash three people purchase raffle tickets. Three winning tickets are selected at random. If first prize is ​$1000​, secon

d prize is ​$500​, and third prize is ​$100​, in how many different ways can the prizes be​ awarded?
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer: 10626

Step-by-step explanation:

Given : The total number of people purchase raffle tickets=23

The total number of prizes = 3

Since , order matters here , so we use Permutations.

The permutation of n things taken r at a time is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Then, the number of ways the prizes can be distributed :-

^{23}P_{3}=\dfrac{23!}{(23-3)!}\\\\=\dfrac{23\times22\times21\times20!}{20!}=10626

Hence, the prizes can be distributed in 10626 ways.

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Luden [163]

Answer:

Z = 2489/533

Step-by-step explanation:

I went on photo math and solved it

7 0
3 years ago
Please help with the top 3 i’ll give u brainliest, what is the volume of the figures below?
jasenka [17]

Answer:

im sorry but i only know the second one, i believe its 224.3

Step-by-step explanation:

8 0
3 years ago
Which expression has an estimated product of 45?<br>44.7x2.1<br>7.5x84<br>8.7x5.28<br>38.1 x 7.3​
Anni [7]

Answer: 8.7 x 5.28

We have to find that expression , which has an estimated product of

1.→44.7 x 2.1

2.→7.5 x 8.4

3.→8.7 x 5.28

4.→38.1 x 7.3

We will start from option 1.

→44.7 x 2.1

44.7 when estimated to nearest tenth=45

2.1, when estimated to nearest tenth=2

44.7 × 2.1=45×2=90

Option 2

7.5 x 8.4

7.5 when estimated to nearest tenth=8

8.4, when estimated to nearest tenth=8

⇒7.5 × 8.4=8×8=64

Option 3

8.7 × 5.28

8.7, when estimated to nearest tenth=9

5.28, when estimated to nearest tenth=5

⇒8.7 × 5.28=9×5=45

Option D

38.1 × 7.3

38.1 when estimated to nearest tenth=38

7.3, when estimated to nearest tenth=7

⇒38×7=266

Option C:⇒8.7 × 5.28 has an estimated product of 45

6 0
3 years ago
Read 2 more answers
A box is to be constructed from a sheet of cardboard that is 10 cm by 60 cm by cutting out squares of length x by x from each co
Stells [14]

Volume of a rectangular box = length x width x height<span>

From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>

<span>
where x is the height of the box or the side of the equal squares from each corner and turning up the sides

V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x

To maximize the volume, we differentiate the expression of the volume and equate it to zero.

V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>

<span>x^2 - 50/3x + 50 = 0

Solving for x,
x1 = 12.74 ;      Volume = -315.56  (cannot be negative)
x2 = 3.92 ;      Volume = 1056.31

So, the answer would be that the maximum volume would be 1056.31 cm^3.
</span><span>
</span>
6 0
3 years ago
Plz plz hlpe wiil make bianleast
Tomtit [17]

Answer-180cm3

Explanation-

The volume of a prism is base x height so v=bh

Here the base equals 4cm times 15m which gives 60cm.And then the height is 3cm.So the total is 15cmx4cmx3cm=180cm³

7 0
3 years ago
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