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grigory [225]
3 years ago
9

Twenty dash three people purchase raffle tickets. Three winning tickets are selected at random. If first prize is ​$1000​, secon

d prize is ​$500​, and third prize is ​$100​, in how many different ways can the prizes be​ awarded?
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer: 10626

Step-by-step explanation:

Given : The total number of people purchase raffle tickets=23

The total number of prizes = 3

Since , order matters here , so we use Permutations.

The permutation of n things taken r at a time is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Then, the number of ways the prizes can be distributed :-

^{23}P_{3}=\dfrac{23!}{(23-3)!}\\\\=\dfrac{23\times22\times21\times20!}{20!}=10626

Hence, the prizes can be distributed in 10626 ways.

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slamgirl [31]

Answer:

Every prism has as many faces, and edges, as its base has sides. Thus, a prism with an octagonal (eight sided) base has eight lateral faces, and eight lateral edges. Each lateral face meets two other lateral faces, as well as the two bases. As a consequence, each lateral face is a four sided polygon.

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3 years ago
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Line m passes through (-5,0) and (-3,2)
nata0808 [166]

Answer:

Yes, they are parallel

Step-by-step explanation:

Find the slopes of the lines using rise over run (y2 - y1) / (x2 - x1)

Find the slope of line M:

(y2 - y1) / (x2 - x1)

(2 - 0) / (-3 + 5)

2/2

= 1

Find the slope of line N:

(y2 - y1) / (x2 - x1)

(4 - 2) / (0 + 2)

2/2

= 1

So, the two lines have the same slope of 1, meaning that they are parallel because parallel lines have the same slope.

They are parallel.

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3 years ago
If a password must have two letters and three digits how many different passwords are possible? ​
Aleks [24]

Answer:

6

Step-by-step explanation:

8 0
3 years ago
If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

10x - 11 = 8x + 23

Subtract 8x from both sides

10x - 11 - 8x = 8x + 23 - 8x

2x - 11 = 23

Add 11 to both sides

2x - 11 + 11 = 23 + 11

2x = 34

Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

x = 17

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0
3 years ago
a boat traveled 14 miles per hour downstream. the trip upstream was at a speed of 10 miles per hour. what is the speed of the bo
MariettaO [177]

Answer:

(im not sure what the first question is asking me)

Speed of the current is 2 miles per hour

Step-by-step explanation:

The reason the current is 2 miles per hour is because it when going down stream they were going 14 miles per hour, going upstream they went 10. The difference is 4mph. So if the current pushes you 2mph when going down stream and holds you 2 mph when going up, the constant speed is 12mph then you add and subtract 2 becuase of the two directions youre traveling. hence 10mph and 14mph.

7 0
3 years ago
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