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ozzi
2 years ago
9

3. How many solutions does the equation have?

Mathematics
1 answer:
Pepsi [2]2 years ago
3 0
An infinite number of solutions since the right side is equal the left side for every value of x.
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Solve x^2 - 8x = 3 by completing the square. Which is the solution set of the equation?​
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Step-by-step explanation:

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(15−x)∙4=10<br> pls pls answer asapppp
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6 0
3 years ago
Select the correct answer.
Anika [276]
<h2>Answer:</h2><h3>A.   \displaystyle{\frac{-(-2) \pm \sqrt{(2)^{2}-4(1)(4)}}{2(1)} }</h3><h2 />

Find the values a, b, and c to substitute into the quadratic formula.

<h2>Remember:</h2><h3>Standard form</h3>

Notice how there are a, b, and c. Everything is left of the equal sign, leaving 0 on the right.

<em>ax² + bx + c = 0</em>

<h3>Quadratic formula</h3>

Notice how there are a, b, and c too, just like in standard form. After we find standard form, we can substitute a, b and c values into the quadratic formula.

\displaystyle{x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} }

<h2>Step-by-step solution</h2>

Here are the steps we will follow:

  1. Rearrange the equation from the question into standard form.
  2. Determine the values for a, b, and c.
  3. Substitute a, b, and c into the quadratic formula.
  4. Compare options and simplify as needed.

<h3>Rearrange into standard form</h3>

Move everything to the left while keeping both sides equal.

x² + 1 = 2x – 3                 Equation from the question

x² + 1 + 3 = 2x – 3 + 3     Add three to both sides.

x² + 1 + 3 = 2x                 -3 + 3 cancels out to 0.

x² + 4 = 2x                      Simplify.

x² + 4 – 2x = 2x – 2x     Subtract 2x from both sides.

x² + 4 – 2x = 0                No numbers on the right side is the same as 0.

x² – 2x + 4 = 0                Rearrange to follow ax² + bx + c = 0.

<h3>Determine a, b, and c values</h3>

Find a, b, and c from standard form.

ax² + bx + c = 0         Standard form

x² – 2x + 4 = 0           No number attached to x² means a = 1.

a = 1,  b = –2,  and  c = 4

<h3>Substitute into the quadratic formula</h3>

Substitute a = 1, b = –2, and c = 4 into the quadratic formula.

\displaystyle{x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} }    

Here is how our formula set up should look:

\displaystyle{x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(4)}}{2(1)} }

<h3>Compare answer options</h3>

Let's compare formula set up to the options in the question.

The denominator is 2(1). So, the answer is <u>not option B</u>.

Inside the square root, it says –4(1)(4). So, the answer is <u>not option D</u>.

This leaves us with either option A or option C.

<h3>Simplify</h3>

Before the ±, it says –(–2). When simplified, –(–2) is 2.

Option C has –2. So, the answer is <u>not option C</u>.

Inside the square root, it says (–2)², which is equal to 2².

When solving exponents of negative numbers,

  • an odd exponent results in a negative product, and;
  • an even exponent results in a positive product.

The exponent 2 is even.

(–2)² = 4

∵ (–2)² = 4 and 2² = 4

∴ (–2)² = 2²

(–2)² is the same as 2².

Therefore, the answer is <u>option A</u>.

5 0
2 years ago
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