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const2013 [10]
3 years ago
6

a baseball diamond is square with each base 90 feet apart, Andy is starting on first base while his teammate Logan is standing b

etween 2nd and 3rd base. if the straight line distance from Andy to Logan is 98 feet, how far is Logan standing from 2nd base? round your answer to the nearest tenth
Mathematics
2 answers:
hodyreva [135]3 years ago
8 0

Answer:

Logan is 45 feet from second base.

Step-by-step explanation:

If you divide 90 by 2 because is 1/2 away then it would be 45

omeli [17]3 years ago
5 0

Answer:

Logan is standing about 38.8 feet past 2nd base.

Step-by-step explanation:

a^2 + b^2 = c^2

90^2 + b^2 = 98^2

b^2 = 98^2 - 90^2

b^2 = 9604 - 8100

b^2 = 1504

b = 38.8

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If θ is an angle in standard position and its terminal side passes through the point (-5,-6), find the exact value of
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Answer:

\sec \theta = -\frac{\sqrt{61}}{5}

Step-by-step explanation:

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6 0
3 years ago
Nine months ago Alexa deposited $7,000 in a three-year CD. She has received $224.16 in interest.
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8 0
3 years ago
Sam initially invested $4,500 into a savings account that offers an interest rate of 3% each year. He wants to determine the num
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\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill&7020\\ P=\textit{original amount deposited}\dotfill & \$4500\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\dotfill \end{cases}


\bf 7020\geqslant 4500(1+0.03t)\implies \cfrac{7020}{4500}\geqslant 1+0.03t\implies \cfrac{39}{25}\geqslant 1+0.03t \\\\\\ \cfrac{39}{25}-1\geqslant 0.03t\implies \cfrac{14}{25}\geqslant 0.03t\implies \cfrac{~~\frac{14}{25}~~}{0.03}\geqslant t\implies \cfrac{56}{3}\geqslant t \\\\\\ 18\frac{2}{3}\geqslant t\impliedby \textit{18 years and 8 months}~\hfill \boxed{0 \leqslant t \leqslant 18\frac{2}{3}} \\\\\\ ~\hspace{34em}


check the picture below.


bearing in mind that "t" cannot be less than 0.

8 0
3 years ago
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