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2 years ago

Please help me, thank you!

Mathematics

1 answer:

Anon25 [30]2 years ago

8 0

Answer:

a = 0.3

b = 0.4

c = 40%

d = 15%

Step-by-step explanation:

There are a total of 10 tick marks. So we know that 1 tick mark = 10%

a has 3 tick marks so you can say it's 0.3

b has 4 tick marks so you can say it's 0.4

c also has 4 tick marks, but it's asking for the percentage, so you get 40%

d is 1 1/2 tick marks. It's also asking for percentage. You know 1 tick = 10% and 1/2 tick = 5* so d = 15%

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Openstudt what are the coordinates of the turning point for the function f(x) = (x − 2)3 + 1? (−2, −1) (−2, 1) (2, −1) (2, 1)

Dominik [7]

f(x) = (x - 2)^3 + 1

Find the derivative:-

f'(x) = 3(x -2)^2 This = 0 at the turning points:-

so 3(x - 2)^2 =

giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1

Answer is (2, 1)

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2 years ago

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2 years ago

On a map of a town, 3 cm represents 150 m. Two points in the town are 1 km apart. How far apart are the two points on the map?

dmitriy555 [2]

Answer:

5000 km

Step-by-step explanation:

We are given that

3 cm represents on a map of a town=150 m

Distance between two points=1 km

We have to find the distance between two points on the map.

3 cm represents on a map of a town=150 m

1 cm represents on a map of a town=150/3 m

1 km=1000 m

1 m=100 cm

$1km=1000\times 100=100000 cm$

100000 cm represents on a map of a town

= $\frac{150}{3}\times 100000$ m

100000 cm represents on a map of a town=5000000 m

100000 cm represents on a map of a town

= $\frac{5000000}{1000} km$

100000 cm represents on a map of a town=5000 km

Hence, two points are separated by 5000 km on the map.

6 0

2 years ago

PLEASE HELP NOW!! thanks:))

algol13

Answer:

I think it is A

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

5 0

2 years ago

Please help me, thank you!​

Please help me, thank you!