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Allisa [31]
3 years ago
14

Please help me, thank you!​

Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

Answer:

a = 0.3

b = 0.4

c = 40%

d = 15%

Step-by-step explanation:

There are a total of 10 tick marks. So we know that 1 tick mark = 10%

a has 3 tick marks so you can say it's 0.3

b has 4 tick marks so you can say it's 0.4

c also has 4 tick marks, but it's asking for the percentage, so you get 40%

d is 1 1/2 tick marks. It's also asking for percentage. You know 1 tick = 10% and 1/2 tick = 5* so d = 15%

You might be interested in
Use slope-intercept form to write the equation of a line
Korvikt [17]

Answer:

y=-3x-2

Step-by-step explanation:

There is enough information to make a point-slope form equation that which we can convert into slope-intercept form.

Point-slope form is: y-y_1=m(x-x_1)

We are given the slope of -3 and the point of (1,-5).

y-y_1=m(x-x_1)\rightarrow y+5=-3(x-1)

Convert into Slope-Intercept Form:

y+5=-3(x-1)\\y+5-5=-3(x-1)-5\\\boxed{y=-3x-2}

8 0
3 years ago
1. -8(1+4x)+7x=-25-8x <br> 2. -5+6(x-7)=-40+5x<br> Could you show the work?
chubhunter [2.5K]

Answer:

1. x=1

2. x=7

Step-by-step explanation:

1. -8(1+4x)+7x=-25-8x

-8-32x+7x=-25-8x

8x-32x+7x=-25+8

-17x=-25+8

-17x=-17

\frac{-17x}{-17} =\frac{-17}{-17} \\x=1

2. -5+6(x-7)=-40+5x

-5+6x-42=-40+5x

-47+6x=-40+5x

x=47-40

x=7

5 0
3 years ago
Exercise Plus charges a yearly fee of $75 plus $10 a month. Gym and Swim charges a yearly fee of $50 plus $15 a month. When , if
Natasha2012 [34]

Answer:

5 months will be the same cost at each gym.

Step-by-step explanation:

As

  • Exercise Plus charges a yearly fee of $75 plus $10 a month.
  • Gym and Swim charges a yearly fee of $50 plus $15 a month.

Let x by the number of months

75+10x=50+15x

10x=15x-25

-5x=-25

\frac{-5x}{-5}=\frac{-25}{-5}

x=5

Therefore, 5 months will be the same cost at each gym.

4 0
3 years ago
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
Can you please help? I know the one I chose is correct.
AleksandrR [38]
I believe you are right :) because they are the same 
7 0
3 years ago
Read 2 more answers
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